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增添高三周末卷04使用数据

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WangWeiye 2023-04-14 09:39:09 +08:00
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工具/文本文件/metadata.txt
View File

@ -1,4 +1,569 @@
ans
usages
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31382
$\begin{cases}\dfrac{2^n+1}{3}, & n = 2k+1, \\ \dfrac{2^n+2}{3}, & n = 2k+2\end{cases}$($k\in \mathbf{N}$)

252
题库0.3/Problems.json
View File

@ -358930,7 +358930,17 @@
"ans": "$(-\\infty,2)$",
"solution": "",
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"ans": "$(-3,5)$",
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"ans": "$\\sqrt{10}$",
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@ -359025,7 +359075,17 @@
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"ans": "$\\dfrac{7}{25}$",
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@ -359082,7 +359162,17 @@
"ans": "$\\dfrac{2\\sqrt{6}}5$",
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@ -359101,7 +359191,17 @@
"ans": "$\\dfrac{3}{10}$",
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"ans": "$10$",
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"20230217\t王伟叶"
@ -359139,7 +359249,17 @@
"ans": "$\\dfrac{3\\pi}{8}$",
"solution": "",
"duration": -1,
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"20230331\t2023届高三02班\t0.516",
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"edit": [
"20230217\t王伟叶"
@ -359158,7 +359278,17 @@
"ans": "C",
"solution": "",
"duration": -1,
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"edit": [
"20230217\t王伟叶"
@ -359177,7 +359307,17 @@
"ans": "D",
"solution": "",
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"edit": [
"20230217\t王伟叶"
@ -359196,7 +359336,17 @@
"ans": "B",
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"20230331\t2023届高三07班\t0.821",
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"edit": [
"20230217\t王伟叶"
@ -359215,7 +359365,17 @@
"ans": "A",
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"20230331\t2023届高三02班\t0.548",
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"20230331\t2023届高三06班\t0.474",
"20230331\t2023届高三07班\t0.536",
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"edit": [
"20230217\t王伟叶"
@ -359234,7 +359394,17 @@
"ans": "(1) $2n-1$; (2) $4n^2+\\dfrac{9^n}{4}-\\dfrac 14$",
"solution": "",
"duration": -1,
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"origin": "2023届黄浦区一模试题试题17",
"edit": [
"20230217\t王伟叶"
@ -359253,7 +359423,17 @@
"ans": "(1) 证明略; (2) $\\dfrac{2\\sqrt{3}}3$",
"solution": "",
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"origin": "2023届黄浦区一模试题试题18",
"edit": [
"20230217\t王伟叶"
@ -359272,7 +359452,17 @@
"ans": "(1) 如设$AE=x$百米, 则$y=4x+8-2\\sqrt{x^2-9}$($3<x<5$); 如设$\\angle MAE=x$, 则$y=\\dfrac{12}{\\cos x}+8-6\\tan x$($0<x<\\arctan\\dfrac 43$)等; (2) 约$18.39$百米",
"solution": "",
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"edit": [
"20230217\t王伟叶"
@ -359291,7 +359481,17 @@
"ans": "(1) $\\dfrac{x^2}8+\\dfrac{y^2}4=1$; (2) 证明略; (3) 斜率的最小值为$\\dfrac{\\sqrt{6}}2$, 此时直线$l_1$的方程为$y=\\dfrac{\\sqrt{6}}6x+\\dfrac{2\\sqrt{7}}7$",
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"origin": "2023届黄浦区一模试题试题20",
"edit": [
"20230217\t王伟叶"
@ -359310,7 +359510,17 @@
"ans": "(1) $f(x)=2^x$是关于$(0,+\\infty)$的同变函数, 不是关于$(0,1)$的同变函数; (2) $f(x)=\\sqrt{2(x-2k)}+2k$, 当$x=2k+\\dfrac 12$($k\\in\\mathbf{Z}$)时, $f(x)=x+\\dfrac 12$, 当$x\\ne 2k+\\dfrac 12$($k\\in\\mathbf{Z}$)时, $f(x)<x+\\dfrac 12$; (3) 证明略",
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"edit": [
"20230217\t王伟叶"