20230217 afternoon
This commit is contained in:
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7ca1a81bec
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 3,
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"execution_count": 7,
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"metadata": {},
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"outputs": [
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{
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"0"
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]
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},
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"execution_count": 3,
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"execution_count": 7,
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"metadata": {},
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"output_type": "execute_result"
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}
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@ -19,7 +19,7 @@
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"source": [
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"import os,re,json\n",
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"\"\"\"这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭, 随后运行第二个代码块\"\"\"\n",
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"problems = \"31205\"\n",
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"problems = \"14039\"\n",
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"\n",
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"def generate_number_set(string,dict):\n",
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" string = re.sub(r\"[\\n\\s]\",\"\",string)\n",
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@ -51,7 +51,7 @@
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"execution_count": 6,
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"metadata": {},
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"outputs": [],
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"source": [
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@ -2,7 +2,7 @@
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 2,
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"execution_count": 5,
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"metadata": {},
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"outputs": [
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{
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@ -11,7 +11,7 @@
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"0"
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]
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},
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"execution_count": 2,
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"execution_count": 5,
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"metadata": {},
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"output_type": "execute_result"
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}
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@ -21,7 +21,7 @@
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"\n",
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"\"\"\"---设置关键字, 同一field下不同选项为or关系, 同一字典中不同字段间为and关系, 不同字典间为or关系, _not表示列表中的关键字都不含, 同一字典中的数字用来供应同一字段不同的条件之间的and---\"\"\"\n",
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"keywords_dict_table = [\n",
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" {\"origin\":[\"百分百\"],\"tags\":[\"第一单元\"]}\n",
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" {\"origin\":[\"奉贤\"],\"origin2\":[\"2023\"],\"origin3\":[\"一模\"]}\n",
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"]\n",
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"\"\"\"---关键字设置完毕---\"\"\"\n",
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"# 示例： keywords_dict_table = [\n",
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@ -11,7 +11,7 @@
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"text": [
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"首个空闲id: 14511 , 直至 020000\n",
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"首个空闲id: 22048 , 直至 030000\n",
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"首个空闲id: 31227 , 直至 999999\n"
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"首个空闲id: 31234 , 直至 999999\n"
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]
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}
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],
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@ -1 +1 @@
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3714,3716,3741,3797,3810,3833,3897,3948,3963,13292,13320,13416,13419,13470,13510,13559,13629,13683,
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012697,012698,012699,012700,012701,012702,012703,012704,012705,012706,012707,012708,012709,012710,012711,012712,012713,012714,012715,012716,012717
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@ -9,8 +9,8 @@
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"import os,re,json,time\n",
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"\n",
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"\"\"\"---设置原题目id与新题目id列表, 新id的数目不能小于旧id的数目---\"\"\"\n",
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"old_ids = \"14365,13966,13975,13088,13100,13145,14003\"\n",
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"new_ids = \"31227:31233\"\n",
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"old_ids = \"13193,13179\"\n",
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"new_ids = \"31234,31235\"\n",
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"\"\"\"---设置完毕---\"\"\"\n",
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"\"\"\"---完成编辑后记得运行第二个单元格---\"\"\"\n",
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"\n",
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@ -2,7 +2,7 @@
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 3,
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"execution_count": 6,
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"metadata": {},
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"outputs": [
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{
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@ -13,9 +13,11 @@
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"题块 1 处理完毕.\n",
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"正在处理题块 2 .\n",
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"题块 2 处理完毕.\n",
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"开始编译教师版本pdf文件: 临时文件/13_解析几何综合_教师_20230214.tex\n",
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"正在处理题块 3 .\n",
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"题块 3 处理完毕.\n",
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"开始编译教师版本pdf文件: 临时文件/高三下学期周末卷03_教师_20230217.tex\n",
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"0\n",
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"开始编译学生版本pdf文件: 临时文件/13_解析几何综合_学生_20230214.tex\n",
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"开始编译学生版本pdf文件: 临时文件/高三下学期周末卷03_学生_20230217.tex\n",
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"0\n"
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]
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}
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@ -28,12 +30,12 @@
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"\"\"\"2: 测验卷与周末卷(填空题, 选择题, 解答题)\"\"\"\n",
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"\"\"\"3: 日常选题讲义(一个section)\"\"\"\n",
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"\n",
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"paper_type = 1 # 随后设置一下后续的讲义标题\n",
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"paper_type = 2 # 随后设置一下后续的讲义标题\n",
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"\n",
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"\"\"\"---设置题块编号---\"\"\"\n",
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"\n",
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"problems = [\n",
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"\"13997,13116,13118,13119,13143,13108,14478,13992,13989,14503,14505,13982,13112,14020,14483\",\"13979,13136,14459,14491,14479,13121,14012,13999,14485,14506,31233,14509,14014,13124,14019\"\n",
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"\"12697:12708\",\"12709:12712\",\"12713:12717\"\n",
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"]\n",
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"\n",
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"\"\"\"---设置结束---\"\"\"\n",
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@ -42,12 +44,12 @@
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"if paper_type == 1:\n",
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" enumi_mode = 0 #设置模式(1为整卷统一编号, 0为每一部分从1开始编号)\n",
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" template_file = \"模板文件/复习讲义模板.txt\" #设置模板文件名\n",
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" exec_list = [(\"标题数字待处理\",\"13\"),(\"标题文字待处理\",\"解析几何综合\")] #设置讲义标题\n",
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" exec_list = [(\"标题数字待处理\",\"10\"),(\"标题文字待处理\",\"空间向量与应用\")] #设置讲义标题\n",
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" destination_file = \"临时文件/\"+exec_list[0][1]+\"_\"+exec_list[1][1] # 设置输出文件名\n",
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"elif paper_type == 2:\n",
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" enumi_mode = 1 #设置模式(1为整卷统一编号, 0为每一部分从1开始编号)\n",
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" template_file = \"模板文件/测验周末卷模板.txt\" #设置模板文件名\n",
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" exec_list = [(\"标题替换\",\"高三下学期测验01\")] #设置讲义标题\n",
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" exec_list = [(\"标题替换\",\"高三下学期周末卷03\")] #设置讲义标题\n",
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" destination_file = \"临时文件/\"+exec_list[0][1] # 设置输出文件名\n",
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"elif paper_type == 3:\n",
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" enumi_mode = 0 #设置模式(1为整卷统一编号, 0为每一部分从1开始编号)\n",
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@ -324224,7 +324224,9 @@
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"20230118\t王伟叶"
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],
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"same": [],
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"related": [],
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"related": [
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"031235"
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],
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"remark": "",
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"space": ""
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},
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@ -324518,7 +324520,9 @@
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"20230118\t王伟叶"
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],
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"same": [],
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"related": [],
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"related": [
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"031234"
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],
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"remark": "",
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"space": ""
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},
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@ -342412,7 +342416,7 @@
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},
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"014039": {
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"id": "014039",
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"content": "已知平面$A_1BC_1$中, $\\overrightarrow{A_1C_1}=(0,1,0)$, $\\overrightarrow{A_1B}=(1,0,1)$, 则平面$A_1BC_1$的一个法向量为$\\overrightarrow {n}=$\\blank{50}.",
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"content": "已知平面$ABC$中, $\\overrightarrow{AC}=(0,1,0)$, $\\overrightarrow{AB}=(1,0,1)$, 则平面$ABC$的一个法向量为$\\overrightarrow {n}=$\\blank{50}.",
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"objs": [],
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"tags": [
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"第六单元"
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@ -350103,7 +350107,7 @@
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},
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"014432": {
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"id": "014432",
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"content": "《九章算术》是我国古代的数学巨著, 其卷第五``商功''有如下的问题: ``今有刍甍, 下广三丈, 衰四丈, 上袲二丈, 无广, 高一丈. 问积几何? ''意思为: 今有底面为矩形的屋脊形状的多面体(如图), 下底面宽$AD=3$丈, 长$AB=4$丈, 上棱$EF=2$丈, $EF$与平面$ABCD$平行, $EF$与平面$ABCD$的距离为$1$丈, 则它的体积是\\blank{50}(立方丈).\n\\begin{center}\n\\begin{tikzpicture}[>=latex, z = {(-120:0.5cm)}]\n\\draw (-2,0,1.5) node [below] {$A$} coordinate (A);\n\\draw (A)++(4,0,0) node [below] {$B$} coordinate (B);\n\\draw (A)++(0,0,-3) node [left] {$D$} coordinate (D);\n\\draw (D)++(4,0,0) node [right] {$C$} coordinate (C);\n\\draw (-1,1,0) node [above] {$E$} coordinate (E);\n\\draw (1,1,0) node [above] {$F$} coordinate (F);\n\\draw (E)--(F)(E)--(A)(F)--(B)(F)--(C)(A)--(B)--(C)(A)--(D)--(E);\n\\draw [dashed] (D)--(C);\n\\end{tikzpicture}\n\\end{center}",
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"content": "《九章算术》是我国古代的数学巨著, 其卷第五``商功''有如下的问题: ``今有刍甍, 下广三丈, 袤四丈, 上袤二丈, 无广, 高一丈. 问积几何? ''意思为: 今有底面为矩形的屋脊形状的多面体(如图), 下底面宽$AD=3$丈, 长$AB=4$丈, 上棱$EF=2$丈, $EF\\parallel AB$, $EF$与平面$ABCD$的距离为$1$丈, 则它的体积是\\blank{50}(立方丈).\n\\begin{center}\n\\begin{tikzpicture}[>=latex, z = {(-120:0.5cm)}]\n\\draw (-2,0,1.5) node [below] {$A$} coordinate (A);\n\\draw (A)++(4,0,0) node [below] {$B$} coordinate (B);\n\\draw (A)++(0,0,-3) node [left] {$D$} coordinate (D);\n\\draw (D)++(4,0,0) node [right] {$C$} coordinate (C);\n\\draw (-1,1,0) node [above] {$E$} coordinate (E);\n\\draw (1,1,0) node [above] {$F$} coordinate (F);\n\\draw (E)--(F)(E)--(A)(F)--(B)(F)--(C)(A)--(B)--(C)(A)--(D)--(E);\n\\draw [dashed] (D)--(C);\n\\end{tikzpicture}\n\\end{center}",
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"objs": [],
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"tags": [],
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"genre": "填空题",
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@ -427811,5 +427815,53 @@
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],
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"remark": "",
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"space": ""
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},
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"031234": {
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"id": "031234",
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"content": "半径为$1$的球面上的四点$A$、$B$、$C$、$D$是正四面体的顶点, $|AB|=$\\blank{50}.",
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"objs": [],
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"tags": [
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"第六单元"
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],
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"genre": "填空题",
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"ans": "",
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"solution": "",
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"duration": -1,
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"usages": [],
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"origin": "2022届高三第二轮复习讲义-20230217修改",
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"edit": [
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"20230118\t王伟叶",
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"20230217\t"
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],
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"same": [],
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"related": [
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"013193"
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],
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"remark": "",
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"space": ""
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},
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"031235": {
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"id": "031235",
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"content": "如图, 半径为$R$的半球$O$的底面圆$O$在平面$\\alpha$内, 过点$O$作平面$\\alpha$的垂线交半球面于点$A$, 过圆$O$的直径$CD$作平面$\\alpha$成$45^{\\circ}$角的平面与半球面相交, 所得交线上到平面$\\alpha$的距离最大的点为$B$, 该交线上的一点$P$满足$\\angle BOP=60^{\\circ}$, 则$|AP|=$\\blank{50}.\n\\begin{center}\n\\begin{tikzpicture}[>=latex]\n\\draw [domain = 0:180,dashed,samples=100] plot ({2*cos(\\x)},0,{-2*sin(\\x)});\n\\draw [domain = 0:180,samples=100] plot ({2* cos(\\x)},0,{2* sin(\\x)});\n\\draw [dashed] (0,0,2) node [below left] {$C$} coordinate (C) -- (0,0,-2) node [above right] {$D$} coordinate (D);\n\\draw [dashed] (0,0,0) node [below right] {$O$} coordinate (O) -- (0,2,0) node [above] {$A$} coordinate (A);\n\\draw [dashed] (O) -- ({-sqrt(2)},{sqrt(2)},0) node [above left] {$B$} coordinate (B);\n\\path [draw,domain = 0:180,samples=100,name path = semi] plot ({2*cos (\\x)},{2*sin(\\x)},0);\n\\draw [domain = 0:90,samples=100] plot ({-sqrt(2)*sin(\\x)},{sqrt(2)*sin(\\x)},{2*cos(\\x)});\n\\draw [domain = 90:180,dashed,samples=100] plot ({-sqrt(2)*sin(\\x)},{sqrt(2)*sin(\\x)},{2*cos(\\x)});\n\\draw ({-sqrt(2)*sin(30)},{sqrt(2)*sin(30)},{2*cos(30)}) node [left] {$P$} coordinate (P);\n\\draw [dashed] (O)--(P);\n\\draw (O) pic [draw,\"$60^\\circ$\",angle eccentricity=1.5] {angle = B--O--P};\n\\path [name path = outline] (-3,0,3) -- (3,0,3) -- (3,0,-3) -- (-3,0,-3) -- cycle;\n\\path [name intersections = {of = semi and outline, by = {S,T}}];\n\\draw (T) -- (-3,0,-3) -- (-3,0,3) -- (3,0,3) -- (3,0,-3) -- (S);\n\\draw [dashed] (S) -- (T);\n\\draw (-2.6,0,2.6) node {$\\alpha$};\n\\end{tikzpicture}\n\\end{center}",
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"objs": [],
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"tags": [
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"第六单元"
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],
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"genre": "填空题",
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"ans": "",
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"solution": "",
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"duration": -1,
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"usages": [],
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"origin": "2022届高三第二轮复习讲义-20230217修改",
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"edit": [
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"20230118\t王伟叶",
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"20230217\t"
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],
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"same": [],
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"related": [
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"013179"
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],
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"remark": "",
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"space": ""
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}
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}
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