From 3f61de19dc0e49004c025a7968390ac40847c9cd Mon Sep 17 00:00:00 2001
From: wangweiye7840 <kj_wangweiye@126.com>
Date: Mon, 29 Jan 2024 10:19:29 +0800
Subject: [PATCH] =?UTF-8?q?=E4=BF=AE=E6=94=B9=E4=B8=80=E4=BA=9B=E9=A2=98?=
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---
 题库0.3/Problems.json | 25 +++++++++++++++----------
 1 file changed, 15 insertions(+), 10 deletions(-)

diff --git a/题库0.3/Problems.json b/题库0.3/Problems.json
index 9015a55d..cdbf6155 100644
--- a/题库0.3/Problems.json
+++ b/题库0.3/Problems.json
@@ -541097,7 +541097,7 @@
     },
     "020144": {
         "id": "020144",
-        "content": "求解下列不等式(组)的解集: \n(1) $2x^2-3x+1<0$;\\\\\n(2) $(x+1)^2-6>0$;\\\\\n(3) $x(x-1)<x(2x-3)+1$;\\\\\n(4) $-x^2+2x+35>0$;\\\\\n(5) $x^4+2x^2-8<0$;\\\\\n(6) $\\begin{cases} 4x^2-27x+18>0, \\\\ x^2-6x+4<0; \\end{cases}$\\\\\n(7) $\\begin{cases} 6-x-x^2\\le 0, \\\\ x^2+3x-4<0; \\end{cases}$\\\\\n(8) $\\begin{cases} 5x^2-4x-7\\le 0, \\\\ x^2+x+1<0, \\\\ 7x-2>0. \\end{cases}$",
+        "content": "求解下列不等式(组)的解集:\\\\\n(1) $2x^2-3x+1<0$;\\\\\n(2) $(x+1)^2-6>0$;\\\\\n(3) $x(x-1)<x(2x-3)+1$;\\\\\n(4) $-x^2+2x+35>0$;\\\\\n(5) $x^4+2x^2-8<0$;\\\\\n(6) $\\begin{cases} 4x^2-27x+18>0, \\\\ x^2-6x+4<0; \\end{cases}$\\\\\n(7) $\\begin{cases} 6-x-x^2\\le 0, \\\\ x^2+3x-4<0; \\end{cases}$\\\\\n(8) $\\begin{cases} 5x^2-4x-7\\le 0, \\\\ x^2+x+1<0, \\\\ 7x-2>0. \\end{cases}$",
         "objs": [],
         "tags": [
             "第一单元"
@@ -541115,7 +541115,8 @@
         ],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20240129\t王伟叶"
         ],
         "same": [],
         "related": [],
@@ -541196,7 +541197,7 @@
     },
     "020147": {
         "id": "020147",
-        "content": "已知$a\\in \\mathbf{R}$, 求下列关于$x$的不等式的解集:\\\\\n(1) $x^2-(a+1)^2x+2a(a^2+1)<0$;\n(2) $x^2+(a+2)x+2a>0$.",
+        "content": "已知$a\\in \\mathbf{R}$, 求下列关于$x$的不等式的解集:\\\\\n(1) $x^2-(a+1)^2x+2a(a^2+1)<0$;\\\\\n(2) $x^2+(a+2)x+2a>0$.",
         "objs": [],
         "tags": [
             "第一单元"
@@ -541214,7 +541215,8 @@
         ],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20240129\t王伟叶"
         ],
         "same": [],
         "related": [
@@ -541643,7 +541645,7 @@
     },
     "020161": {
         "id": "020161",
-        "content": "求下列不等式的解集: \n(1) $\\dfrac 1x<1$;\\\\\n(2) $\\dfrac{4x+3}{x-1}>5$;\\\\\n(3) $\\dfrac 2x<\\dfrac 2{x-3}$;\\\\\n(4) $\\dfrac{x+4}{x^2+2x+2}\\le 1$.",
+        "content": "求下列不等式的解集:\\\\\n(1) $\\dfrac 1x<1$;\\\\\n(2) $\\dfrac{4x+3}{x-1}>5$;\\\\\n(3) $\\dfrac 2x<\\dfrac 2{x-3}$;\\\\\n(4) $\\dfrac{x+4}{x^2+2x+2}\\le 1$.",
         "objs": [],
         "tags": [
             "第一单元"
@@ -541655,7 +541657,8 @@
         "usages": [],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20240129\t王伟叶"
         ],
         "same": [],
         "related": [],
@@ -542999,7 +543002,7 @@
     },
     "020204": {
         "id": "020204",
-        "content": "已知$x>1$.比较大小: $\\dfrac{2x^2-4x+4}{x-1}$\\blank{50}",
+        "content": "已知$x>1$.比较大小: $\\dfrac{2x^2-4x+4}{x-1}$\\blank{50}$4$.",
         "objs": [],
         "tags": [
             "第一单元"
@@ -543011,7 +543014,8 @@
         "usages": [],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20240129\t王伟叶"
         ],
         "same": [],
         "related": [],
@@ -543491,7 +543495,7 @@
     },
     "020222": {
         "id": "020222",
-        "content": "已知$ab>0$, 且$a+b=1$.求证: $\\sqrt {a+\\dfrac 12}+\\sqrt {b+\\dfrac 12}\\le 2$.",
+        "content": "已知$a,b>0$, 且$a+b=1$.求证: $\\sqrt {a+\\dfrac 12}+\\sqrt {b+\\dfrac 12}\\le 2$.",
         "objs": [],
         "tags": [
             "第一单元"
@@ -543503,7 +543507,8 @@
         "usages": [],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20240129\t王伟叶"
         ],
         "same": [],
         "related": [],