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和K0108,K0207有关的题目和备课稿题号的修改

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wangweiye7840 2023-07-19 12:49:01 +08:00
parent 8a8d2636e4
commit 465d6f1bb0
2 changed files with 151 additions and 7 deletions
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12
工具v2/文本文件/备课稿题号.json
View File

@ -44,6 +44,18 @@
"集合与逻辑章节复习题": [
"1:11,30001,13:19"
],
"K0108": [
"11783,11784,19275",
"19276",
"9444,9445,10041",
"20097:20099,20101,20100,20102:20104"
],
"K0207": [
"11882,19277,19278",
"19279",
"20406:20410",
"11885:11886,9485,65,10129:10130,10135,20405,20411,10131"
],
"K0215": [
"11924,11925,11926",
"11930",

146
题库0.3/Problems.json
View File

@ -311564,7 +311564,8 @@
],
"same": [],
"related": [
"011789"
"011789",
"019275"
],
"remark": "",
"space": "4em",
@ -311588,7 +311589,8 @@
],
"same": [],
"related": [
"011788"
"011788",
"019275"
],
"remark": "",
"space": "4em",
@ -311611,7 +311613,9 @@
"20220901\t王伟叶"
],
"same": [],
"related": [],
"related": [
"019276"
],
"remark": "",
"space": "4em",
"unrelated": []
@ -313699,7 +313703,8 @@
"same": [],
"related": [
"011882",
"011884"
"011884",
"019277"
],
"remark": "",
"space": "4em",
@ -313724,7 +313729,8 @@
"same": [],
"related": [
"011882",
"011883"
"011883",
"019278"
],
"remark": "",
"space": "4em",
@ -493728,6 +493734,131 @@
"space": "4em",
"unrelated": []
},
"019275": {
"id": "019275",
"content": "设$k$为实数, 求以下关于$x$与$y$的二元一次方程组的解集.\\\\n(1) $\\begin{cases} y=(3-2k)x-2, \\\\ y=k^2x-1; \\end{cases}$\\\\\n(2) $\\begin{cases} y=x+k^2+2k, \\\\ y=k^2x+3. \\end{cases}$",
"objs": [],
"tags": [
"第一单元"
],
"genre": "4em",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "空中课堂必修第一册例题与习题-20230719修改",
"edit": [
"20220901\t王伟叶",
"20230719\t赵琍琍"
],
"same": [],
"related": [
"011789",
"011788"
],
"remark": "",
"space": "4em",
"unrelated": []
},
"019276": {
"id": "019276",
"content": "设$x$、$y$均为整数, 求以下关于$x$与$y$的方程的解集.\\\\\n(1) $|x-2|+|y-1|=1$;\\\\\n(2) $(x-2)^2+(y-1)^2=25$.",
"objs": [],
"tags": [
"第一单元"
],
"genre": "4em",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "空中课堂必修第一册例题与习题-20230719修改",
"edit": [
"20220901\t王伟叶",
"20230719\t赵琍琍"
],
"same": [],
"related": [
"011790"
],
"remark": "",
"space": "4em",
"unrelated": []
},
"019277": {
"id": "019277",
"content": "写出幂函数$y=x^3$的定义域, 说明其图像关于原点对称的理由, 并作出它的大致图像.",
"objs": [],
"tags": [
"第二单元"
],
"genre": "4em",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "空中课堂必修第一册例题与习题-20230719修改",
"edit": [
"20220901\t王伟叶",
"20230719\t严捷"
],
"same": [],
"related": [
"011882",
"011884",
"011883"
],
"remark": "",
"space": "4em",
"unrelated": []
},
"019278": {
"id": "019278",
"content": "写出幂函数$y=x^{-\\frac 23}$的定义域, 说明其图像关于$y$轴对称的理由, 并作出它的大致图像.",
"objs": [],
"tags": [
"第二单元"
],
"genre": "4em",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "空中课堂必修第一册例题与习题-20230719修改",
"edit": [
"20220901\t王伟叶",
"20230719\t严捷"
],
"same": [],
"related": [
"011882",
"011883",
"011884"
],
"remark": "",
"space": "4em",
"unrelated": []
},
"019279": {
"id": "019279",
"content": "已知幂函数 $y=x^s$, $y=x^t$ 的图像在第一象限内的部分关于直线 $y=x$ 对称, 则 $s, t$ 应该满足什么关系式, 为什么?",
"objs": [],
"tags": [],
"genre": "解答题",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "自拟题目",
"edit": [
"20230719\t严捷"
],
"same": [],
"related": [],
"remark": "",
"space": "4em",
"unrelated": []
},
"020001": {
"id": "020001",
"content": "判断下列各组对象能否组成集合, 若能组成集合, 指出是有限集还是无限集.\\\\\n(1) 上海市控江中学$2022$年入学的全体高一年级新生;\\\\\n(2) 中国现有各省的名称;\\\\\n(3) 太阳、$2$、上海市;\\\\\n(4) 大于$10$且小于$15$的有理数;\\\\\n(5) 末位是$3$的自然数;\\\\\n(6) 影响力比较大的中国数学家;\\\\\n(7) 方程$x^2+x-3=0$的所有实数解;\\\\ \n(8) 函数$y=\\dfrac 1x$图像上所有的点;\\\\ \n(9) 在平面直角坐标系中, 到定点$(0, 0)$的距离等于$1$的所有点;\\\\\n(10) 不等式$3x-10<0$的所有正整数解;\\\\\n(11) 所有的平面四边形.",
@ -496414,7 +496545,7 @@
},
"020104": {
"id": "020104",
"content": "已知$a\\in \\mathbf{R}$, 要使方程组$\\begin{cases} 2x+ay=16, \\\\x-2y=0 \\end{cases}$有正整数解, 求整数组成$a$的集合.",
"content": "已知$a\\in \\mathbf{Z}$, 要使方程组$\\begin{cases} 2x+ay=16, \\\\x-2y=0 \\end{cases}$有正整数解, 求整数$a$组成的集合.",
"objs": [],
"tags": [
"第一单元"
@ -496426,7 +496557,8 @@
"usages": [],
"origin": "2025届高一校本作业必修第二章",
"edit": [
"20220901\t王伟叶\t伍杨超"
"20220901\t王伟叶\t伍杨超",
"20230719\t赵琍琍"
],
"same": [],
"related": [],