改正一些格式错误的答案
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@ -265498,7 +265498,7 @@
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"009975": {
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"id": "009975",
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"content": "将学生甲所给的线性方程$y=-0.5x+5.0$作为下表中数据的线性拟合, 计算各数据点的离差, 再计算拟合误差. \n\\begin{center}\n\\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}\n\\hline\n每千克价格／百元 & $4.0$ & $4.0$ & $4.6$ & $5.0$ & $5.2$ & $5.6$ & $6.0$ & $6.6$ & $7.0$ & $10.0$ \\\\ \\hline\n年需求量／千克 & $3.5$ & $3.0$ & $2.7$ & $2.4$ & $2.5$ & $2.0$ & $1.5$ & $1.2$ & $1.2$ & $1.0$ \\\\ \\hline\n\\end{tabular}\n\\end{center}\n把结果与下表的数据相比较, \n\\begin{center}\n\\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}\n\\hline\n$x$ & $4.0$ & $4.0$ & $4.6$ & $5.0$ & $5.2$ & $5.6$ & $6.0$ & $6.6$ & $7.0$ & $10$ \\\\ \\hline\n$y$ & $3.5$ & $3.0$ & $2.7$ & $2.4$ & $2.5$ & $2.0$ & $1.5$ & $1.2$ & $1.2$ & $1.0$ \\\\ \\hline\n$\\hat{y}$ & $2.8$ & $2.8$ & $2.6$ & $2.4$ & $2.3$ & $2.2$ & $2.0$ & $1.8$ & $1.6$ & $0.4$ \\\\ \\hline\n离差$y_i-\\hat{y_i}$ & $0.7$ & $0.2$ & $0.1$ & $0.0$ & $0.2$ & $-0.2$ & $-0.5$ & $-0.6$ & $-0.4$ & $0.6$ \\\\ \\hline\n\\end{tabular}\n\\end{center}\n说说你对``最佳拟合$''$有什么新的理解和体会.",
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"content": "将学生甲所给的线性方程$y=-0.5x+5.0$作为下表中数据的线性拟合, 计算各数据点的离差, 再计算拟合误差. \n\\begin{center}\n\\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}\n\\hline\n每千克价格/百元 & $4.0$ & $4.0$ & $4.6$ & $5.0$ & $5.2$ & $5.6$ & $6.0$ & $6.6$ & $7.0$ & $10.0$ \\\\ \\hline\n年需求量/千克 & $3.5$ & $3.0$ & $2.7$ & $2.4$ & $2.5$ & $2.0$ & $1.5$ & $1.2$ & $1.2$ & $1.0$ \\\\ \\hline\n\\end{tabular}\n\\end{center}\n把结果与下表的数据相比较, \n\\begin{center}\n\\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}\n\\hline\n$x$ & $4.0$ & $4.0$ & $4.6$ & $5.0$ & $5.2$ & $5.6$ & $6.0$ & $6.6$ & $7.0$ & $10$ \\\\ \\hline\n$y$ & $3.5$ & $3.0$ & $2.7$ & $2.4$ & $2.5$ & $2.0$ & $1.5$ & $1.2$ & $1.2$ & $1.0$ \\\\ \\hline\n$\\hat{y}$ & $2.8$ & $2.8$ & $2.6$ & $2.4$ & $2.3$ & $2.2$ & $2.0$ & $1.8$ & $1.6$ & $0.4$ \\\\ \\hline\n离差$y_i-\\hat{y_i}$ & $0.7$ & $0.2$ & $0.1$ & $0.0$ & $0.2$ & $-0.2$ & $-0.5$ & $-0.6$ & $-0.4$ & $0.6$ \\\\ \\hline\n\\end{tabular}\n\\end{center}\n说说你对``最佳拟合''有什么新的理解和体会.",
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"objs": [],
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"tags": [
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"第九单元"
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@ -265510,7 +265510,8 @@
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"usages": [],
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"origin": "新教材选择性必修第二册课堂练习",
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"20220730\t王伟叶",
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@ -591221,7 +591222,7 @@
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"第七单元"
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],
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"genre": "解答题",
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"ans": "(1) $\\cos\\theta=\\dfrac{1}{3}$}; (2) $2(x-\\dfrac{1}{2})^2-(y-\\dfrac{\\sqrt{2}}{2})^2=1$; (3) $(-4-3\\sqrt{2},-\\sqrt{2})\\cup (-\\sqrt{2},\\dfrac{-4-\\sqrt{2}}{7})",
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"ans": "(1) $\\cos\\theta=\\dfrac{1}{3}$; (2) $2(x-\\dfrac{1}{2})^2-(y-\\dfrac{\\sqrt{2}}{2})^2=1$; (3) $(-4-3\\sqrt{2},-\\sqrt{2})\\cup (-\\sqrt{2},\\dfrac{-4-\\sqrt{2}}{7})$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -591237,7 +591238,8 @@
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"origin": "2024届高二下学期周末卷02",
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"edit": [
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"20230223\t王伟叶"
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"20230223\t王伟叶",
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"004659"
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@ -593750,7 +593752,7 @@
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"第七单元"
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],
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"genre": "解答题",
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"ans": "(1) $k=\\pm 1$}; (2) $(-\\sqrt{3},-1)\\cup (1,\\sqrt{3})$; (3) 不存",
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"ans": "(1) $k=\\pm 1$; (2) $(-\\sqrt{3},-1)\\cup (1,\\sqrt{3})$; (3) 不存在",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -593768,7 +593770,8 @@
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],
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"origin": "2024届高二下学期周末卷03",
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"edit": [
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"20230302\t王伟叶"
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"20230302\t王伟叶",
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"20230717\t王伟叶"
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"same": [],
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@ -593806,7 +593809,7 @@
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"第七单元"
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],
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"genre": "解答题",
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"ans": "(1) $\\dfrac{x^2}{2}+y^2=1$; (2) $(\\dfrac{2}{3},0)$}; (3) $S_{\\max}=\\dfrac{1}{9}",
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"ans": "(1) $\\dfrac{x^2}{2}+y^2=1$; (2) $(\\dfrac{2}{3},0)$; (3) $S_{\\max}=\\dfrac{1}{9}$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -593824,7 +593827,8 @@
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],
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"origin": "2024届高二下学期周末卷03",
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"edit": [
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"20230302\t王伟叶"
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"20230302\t王伟叶",
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"20230717\t王伟叶"
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"same": [],
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@ -594486,7 +594490,7 @@
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"第二单元"
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],
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"genre": "解答题",
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"ans": "(1) $f(x)=\\dfrac{\\sqrt{x}+1}{x+3}$},定义域为$[0,a]$; (2)$[\\dfrac{1}{3},\\dfrac{6}{13}]$; (3) $a\\in \\{1,2,3,4,5,6,7,8,9\\}",
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"ans": "(1) $f(x)=\\dfrac{\\sqrt{x}+1}{x+3}$,定义域为$[0,a]$; (2)$[\\dfrac{1}{3},\\dfrac{6}{13}]$; (3) $a\\in \\{1,2,3,4,5,6,7,8,9\\}$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -594504,7 +594508,8 @@
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],
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"origin": "2024届高二下学期周末卷04",
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"edit": [
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"20230307\t王伟叶"
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"20230307\t王伟叶",
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"20230717\t王伟叶"
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"same": [],
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@ -595066,7 +595071,7 @@
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"第二单元"
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],
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"genre": "填空题",
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"ans": "(1) $3x^2-2x-1$; (2) $(-\\infty,-\\dfrac{1}{3}]$与$[1,+\\infty)$}; (3) $[-\\dfrac{1}{3},1]$; (4) $1-\n\\dfrac{1}{x}$; (5) $[1,+\\infty)$; (6) $(0,1]$; (7) $-2\\cos (\\dfrac{\\pi}{3}-2x)$ ; (8) $[k\\pi-\\dfrac{7\\pi}{12},k\\pi-\\dfrac{\\pi}{12}],k\\in Z$; (9) $[k\\pi-\\dfrac{\\pi}{12},k\\pi+\\dfrac{5\\pi}{12}],k\\in Z$; (10) $2^x+x 2^x\\ln{2}$; (11) $[-\\ln{2},+\\infty)$; (12) $(-\\infty,-\\ln{2}]$; (13) $4x-\\dfrac{1}{2}x^{-\\frac{1}{2}}$; (14) $[\\dfrac{1}{4},+\\infty)$; (15) $[0,\\dfrac{1}{4}]",
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"ans": "(1) $3x^2-2x-1$; (2) $(-\\infty,-\\dfrac{1}{3}]$与$[1,+\\infty)$; (3) $[-\\dfrac{1}{3},1]$; (4) $1-\n\\dfrac{1}{x}$; (5) $[1,+\\infty)$; (6) $(0,1]$; (7) $-2\\cos (\\dfrac{\\pi}{3}-2x)$ ; (8) $[k\\pi-\\dfrac{7\\pi}{12},k\\pi-\\dfrac{\\pi}{12}],k\\in Z$; (9) $[k\\pi-\\dfrac{\\pi}{12},k\\pi+\\dfrac{5\\pi}{12}],k\\in Z$; (10) $2^x+x 2^x\\ln{2}$; (11) $[-\\ln{2},+\\infty)$; (12) $(-\\infty,-\\ln{2}]$; (13) $4x-\\dfrac{1}{2}x^{-\\frac{1}{2}}$; (14) $[\\dfrac{1}{4},+\\infty)$; (15) $[0,\\dfrac{1}{4}]$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -595078,7 +595083,8 @@
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],
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"origin": "2024届高二下学期周末卷05",
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"edit": [
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"20230318\t王伟叶"
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"20230318\t王伟叶",
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"20230717\t王伟叶"
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],
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"same": [],
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@ -595094,7 +595100,7 @@
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"第二单元"
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],
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"genre": "填空题",
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"ans": "(1)$\\{x\\big {|}x=k\\pi,k\\in Z\\}$}; (2)$\\{x\\big{|}x=\\dfrac{\\pi}{6}+2k\\pi$或$x=\\dfrac{5\\pi}{6}+2k\\pi,k\\in Z\\}",
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"ans": "(1)$\\{x\\big {|}x=k\\pi,k\\in Z\\}$; (2)$\\{x\\|x=\\dfrac{\\pi}{6}+2k\\pi$或$x=\\dfrac{5\\pi}{6}+2k\\pi,k\\in Z\\}$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -595106,7 +595112,8 @@
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],
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"origin": "2024届高二下学期周末卷05",
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"edit": [
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"20230318\t王伟叶"
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"20230318\t王伟叶",
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"20230717\t王伟叶"
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],
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"same": [],
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"related": [],
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@ -595357,7 +595364,7 @@
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"第二单元"
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],
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"genre": "填空题",
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"ans": "(1) $(\\dfrac{1}{3},\\ln{\\dfrac{1}{3}})$}; (2) $(\\ln{\\dfrac{1}{3}}-1,+\\infty)",
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"ans": "(1) $(\\dfrac{1}{3},\\ln{\\dfrac{1}{3}})$; (2) $(\\ln{\\dfrac{1}{3}}-1,+\\infty)$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -595369,7 +595376,8 @@
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],
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"origin": "2024届高二下学期周末卷05",
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"edit": [
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"20230318\t王伟叶"
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"20230318\t王伟叶",
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"20230717\t王伟叶"
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],
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"same": [],
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"related": [],
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@ -598487,7 +598495,7 @@
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"第二单元"
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],
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"genre": "解答题",
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"ans": "递增区间$[-\\ln a,+\\infty)$,递减区间$(-\\infty,-\\ln a]$}; (2) $[1,+\\infty)",
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"ans": "递增区间$[-\\ln a,+\\infty)$,递减区间$(-\\infty,-\\ln a]$; (2) $[1,+\\infty)$",
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"solution": "",
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"duration": -1,
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"usages": [
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@ -598503,7 +598511,8 @@
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],
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"origin": "2024届高二下学期周末卷07",
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"20230324\t王伟叶"
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"20230324\t王伟叶",
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"20230717\t王伟叶"
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