修改021778,021787:021788答案及题面

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weiye.wang 2024-02-24 13:06:44 +08:00
parent 8f83080917
commit 4db3bb10ef
1 changed files with 9 additions and 6 deletions

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@ -592990,7 +592990,7 @@
"第五单元" "第五单元"
], ],
"genre": "解答题", "genre": "解答题",
"ans": "$x=4$, $y=1$.", "ans": "$x=4$, $y=-1$.",
"solution": "", "solution": "",
"duration": -1, "duration": -1,
"usages": [ "usages": [
@ -593005,7 +593005,8 @@
], ],
"origin": "2025届高一下校本作业", "origin": "2025届高一下校本作业",
"edit": [ "edit": [
"20230209\t王伟叶" "20230209\t王伟叶",
"20240224\t王伟叶"
], ],
"same": [ "same": [
"008547" "008547"
@ -593271,7 +593272,7 @@
"第五单元" "第五单元"
], ],
"genre": "解答题", "genre": "解答题",
"ans": "(1) 当$t=\\dfrac{3}{2}$时,点$P$在$x$轴上; 当$t=\\dfrac{1}{3}$时,点$P$在$y$轴上;当$-\\dfrac{2}{3}<t<-\\dfrac{1}{3}$时,点$P$在第二象限;\\\\\n(2) 四边形$OABP$不能构成平行四边形.", "ans": "(1) 当$t=-\\dfrac{3}{2}$时,点$P$在$x$轴上; 当$t=-\\dfrac{1}{3}$时,点$P$在$y$轴上;当$-\\dfrac{2}{3}<t<-\\dfrac{1}{3}$时,点$P$在第二象限;\\\\\n(2) 四边形$OABP$不能构成平行四边形.",
"solution": "", "solution": "",
"duration": -1, "duration": -1,
"usages": [ "usages": [
@ -593286,7 +593287,8 @@
], ],
"origin": "2025届高一下校本作业", "origin": "2025届高一下校本作业",
"edit": [ "edit": [
"20230209\t王伟叶" "20230209\t王伟叶",
"20240224\t王伟叶"
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@ -593296,7 +593298,7 @@
}, },
"021788": { "021788": {
"id": "021788", "id": "021788",
"content": "在四边形$ABCD$中, $\\overrightarrow{AB}=(6,1)$, $\\overrightarrow{BC}=(x,y)$, $\\overrightarrow{CD}=(-2,-3)$.\n(1) 若$\\overrightarrow{BC}\\parallel \\overrightarrow{DA}$, 试求$x$、$y$满足的关系式;\\\\\n(2) 满足(1)的同时, 又有$\\overrightarrow{AC} \\perp \\overrightarrow{BD}$, 求$x$、$y$的值及四边形$ABCD$的面积.", "content": "在四边形$ABCD$中, $\\overrightarrow{AB}=(6,1)$, $\\overrightarrow{BC}=(x,y)$, $\\overrightarrow{CD}=(-2,-3)$.\\\\\n(1) 若$\\overrightarrow{BC}\\parallel \\overrightarrow{DA}$, 试求$x$、$y$满足的关系式;\\\\\n(2) 满足(1)的同时, 又有$\\overrightarrow{AC} \\perp \\overrightarrow{BD}$, 求$x$、$y$的值及四边形$ABCD$的面积.",
"objs": [], "objs": [],
"tags": [ "tags": [
"第五单元" "第五单元"
@ -593317,7 +593319,8 @@
], ],
"origin": "2025届高一下校本作业", "origin": "2025届高一下校本作业",
"edit": [ "edit": [
"20230209\t王伟叶" "20230209\t王伟叶",
"20240224\t王伟叶"
], ],
"same": [], "same": [],
"related": [], "related": [],