录入一些答案

This commit is contained in:
weiye.wang 2024-03-19 21:36:15 +08:00
parent 5fbbb77720
commit 614affee14
2 changed files with 74 additions and 33 deletions

View File

@ -1,24 +1,65 @@
remark
ans
018418
证明略
018419
正三角形
021631
(20240319主要错因) (2)能找到符合要求的锐角或者钝角, 但不能正确写出其它的角
018420
$\sqrt{17}$或$\sqrt{65}$
021623
(20240319主要错因) 没按题目要求写出形状; 基本不等式没有写出何时取等号; 不能正确运用基本不等式求解最值
018421
(1) $x=\arcsin\dfrac{1}{3}+2k\pi$或$\pi-\arcsin\dfrac{1}{3}+2k\pi$, $k\in \mathbf{Z}$; (2) $x=\pi-\arccos\dfrac{3}{5}$; (3) $x=\pi-\arctan 3$
021627
(20240319主要错因) 方法不会
009585
$\sqrt{21}$
021628
(20240319主要错因) (3)没能清楚阐述如何根据题目条件确定角的范围; 不能根据题目条件取舍解
009586
证明略
009587
证明略
009588
(1) $x=\arcsin\dfrac{3}{5}$; (2) $x=\pi-\arccos\dfrac{2}{3}$; (3) $x=-\arctan 2$; (4) $x=-\arcsin\dfrac{2}{3}+2k\pi$或$\pi+\arcsin\dfrac{2}{3}+2k\pi$, $k\in \mathbf{Z}$
018423
(20240319主要错因) (2)方法不会; 不能正确运用基本不等式求解最值; 基本不等式没有写出何时取等号
(1) $\dfrac{2\pi}{3}$; (2) $\dfrac{4\sqrt{3}}{3}$
018424
正三角形
006417
证明略
024616
(20240319主要错因) 方法不会
证明略
024617
(20240319主要错因) 没能清楚阐述如何根据题目条件确定角的范围
等腰三角形($C$为顶角)或直角三角形($c$为斜边)
018425
高度约为$420$米
018426
距离为$21$海里
018427
约南偏西$58.21^\circ$($140^\circ-\arccos\dfrac{1}{7}$)
009589
$6\sqrt{2}$海里
009590
北偏东约$28.13^\circ$方向追击走私船
009591
隧道$DE$的长约为$421$米
018428
(1) $3\sqrt{3}-3$千米; (2) $S=\sqrt{48t^2-24t+7}$, $t\in [0,+\infty)$($t\in [0,\dfrac{3}{4}]$, $t\in [0,\dfrac{3\sqrt{3}}{4}-1]$等均有道理)
018433
(1) 约为$16.310$千米; (2) 约为$35.752$千米

View File

@ -190706,7 +190706,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "证明略",
"solution": "",
"duration": -1,
"usages": [],
@ -273968,7 +273968,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "$\\sqrt{21}$",
"solution": "",
"duration": -1,
"usages": [],
@ -273990,7 +273990,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "证明略",
"solution": "",
"duration": -1,
"usages": [
@ -274017,7 +274017,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "证明略",
"solution": "",
"duration": -1,
"usages": [],
@ -274041,7 +274041,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "(1) $x=\\arcsin\\dfrac{3}{5}$; (2) $x=\\pi-\\arccos\\dfrac{2}{3}$; (3) $x=-\\arctan 2$; (4) $x=-\\arcsin\\dfrac{2}{3}+2k\\pi$或$\\pi+\\arcsin\\dfrac{2}{3}+2k\\pi$, $k\\in \\mathbf{Z}$",
"solution": "",
"duration": -1,
"usages": [],
@ -274063,7 +274063,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "$6\\sqrt{2}$海里",
"solution": "",
"duration": -1,
"usages": [],
@ -274085,7 +274085,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "北偏东约$28.13^\\circ$方向追击走私船",
"solution": "",
"duration": -1,
"usages": [],
@ -274107,7 +274107,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "隧道$DE$的长约为$421$米",
"solution": "",
"duration": -1,
"usages": [],
@ -509335,7 +509335,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "证明略",
"solution": "",
"duration": -1,
"usages": [],
@ -509357,7 +509357,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "正三角形",
"solution": "",
"duration": -1,
"usages": [],
@ -509379,7 +509379,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "$\\sqrt{17}$或$\\sqrt{65}$",
"solution": "",
"duration": -1,
"usages": [],
@ -509401,7 +509401,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "(1) $x=\\arcsin\\dfrac{1}{3}+2k\\pi$或$\\pi-\\arcsin\\dfrac{1}{3}+2k\\pi$, $k\\in \\mathbf{Z}$; (2) $x=\\pi-\\arccos\\dfrac{3}{5}$; (3) $x=\\pi-\\arctan 3$",
"solution": "",
"duration": -1,
"usages": [],
@ -509445,7 +509445,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "(1) $\\dfrac{2\\pi}{3}$; (2) $\\dfrac{4\\sqrt{3}}{3}$",
"solution": "",
"duration": -1,
"usages": [],
@ -509467,7 +509467,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "正三角形",
"solution": "",
"duration": -1,
"usages": [],
@ -509489,7 +509489,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "高度约为$420$米",
"solution": "",
"duration": -1,
"usages": [],
@ -509511,7 +509511,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "距离为$21$海里",
"solution": "",
"duration": -1,
"usages": [],
@ -509533,7 +509533,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "约南偏西$58.21^\\circ$($140^\\circ-\\arccos\\dfrac{1}{7}$)",
"solution": "",
"duration": -1,
"usages": [],
@ -509555,7 +509555,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "(1) $3\\sqrt{3}-3$千米; (2) $S=\\sqrt{48t^2-24t+7}$, $t\\in [0,+\\infty)$($t\\in [0,\\dfrac{3}{4}]$, $t\\in [0,\\dfrac{3\\sqrt{3}}{4}-1]$等均有道理)",
"solution": "",
"duration": -1,
"usages": [],
@ -509669,7 +509669,7 @@
"第三单元"
],
"genre": "解答题",
"ans": "",
"ans": "(1) 约为$16.310$千米; (2) 约为$35.752$千米",
"solution": "",
"duration": -1,
"usages": [],
@ -683738,7 +683738,7 @@
"第三单元"
],
"genre": "4em",
"ans": "",
"ans": "证明略",
"solution": "",
"duration": -1,
"usages": [],
@ -683763,7 +683763,7 @@
"第三单元"
],
"genre": "4em",
"ans": "",
"ans": "等腰三角形($C$为顶角)或直角三角形($c$为斜边)",
"solution": "",
"duration": -1,
"usages": [],