修改14913题面
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import os,re,json
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import os,re,json
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"""这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭"""
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"""这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭"""
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problems = "000638,004082,000430,000840,011540"
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problems = "14913"
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editor = "王伟叶"
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editor = "王慎有"
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def generate_number_set(string,dict):
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def generate_number_set(string,dict):
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string = re.sub(r"[\n\s]","",string)
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string = re.sub(r"[\n\s]","",string)
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@ -388297,7 +388297,7 @@
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},
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},
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"014913": {
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"014913": {
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"id": "014913",
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"id": "014913",
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"content": "已知平面上的线段$l$及点$P$. 任取$l$上一点$Q$, 线段$PQ$长度的最小值称为点$P$到线段$l$的距离, 记作$d(P, l)$. 设线段$l_1: y=2$($-2 \\leq x \\leq 2)$.\\\\\n(1) 分别求点$P_1(0,3)$、$P_2(4,3)$到线段$l_1$的距离$d(P_1, l_1)$、$d(P_2, l_1)$;\\\\\n(2) 求点的集合$D=\\{P | d(P, l)=1\\}$;\\\\\n(3) 设$A(0,2)$, 写出$\\Omega=\\{P|d(P, l_1)=| PA |\\}$.",
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"content": "已知平面上的线段$l$及点$P$. 任取$l$上一点$Q$, 线段$PQ$长度的最小值称为点$P$到线段$l$的距离, 记作$d(P, l)$. 设线段$l_1: y=2$($-2 \\leq x \\leq 2)$.\\\\\n(1) 分别求点$P_1(0,3)$、$P_2(4,3)$到线段$l_1$的距离$d(P_1, l_1)$、$d(P_2, l_1)$;\\\\\n(2) 求点的集合$D=\\{P | d(P, l_1)=1\\}$;\\\\\n(3) 设$A(0,2)$, 写出$\\Omega=\\{P|d(P, l_1)=| PA |\\}$.",
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"objs": [],
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"objs": [],
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"tags": [],
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"tags": [],
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"genre": "解答题",
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"genre": "解答题",
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@ -388307,7 +388307,8 @@
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"usages": [],
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"usages": [],
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"origin": "2022届第三轮复习讲义-阅读新情境并作转化",
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"origin": "2022届第三轮复习讲义-阅读新情境并作转化",
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"edit": [
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"edit": [
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"20230411\t王伟叶"
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"20230411\t王伟叶",
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"20230428\t王慎有"
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],
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],
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"same": [],
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"same": [],
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"related": [],
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"related": [],
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