录入双基百分百2022前15讲答案

工具/文本文件/metadata.txt

@@ -1,242 +1,682 @@
-usages
+ans
 
-021739
-20230425	2025届高一11班	0.976
+13287
+$2$
 
-021740
-20230425	2025届高一11班	1.000
+13288
+$a>2$
 
-021741
-20230425	2025届高一11班	0.976	0.976	1.000	0.976
+13289
+$89$
 
-021742
-20230425	2025届高一11班	0.857
+13290
+$[-1,2]$
 
-021743
-20230425	2025届高一11班	0.774
+13291
+$12$
 
-021744
-20230425	2025届高一11班	0.929
+13292
+$\dfrac{3\sqrt{2}}{4}$
 
-021745
-20230425	2025届高一11班	0.952	0.833
+13293
+$16$
 
-021746
-20230425	2025届高一11班	0.809
+13294
+$\arctan \dfrac{\sqrt{6}}6$
 
-021747
-20230425	2025届高一11班	1.000
+13295
+$\dfrac 56$
 
-021748
-20230425	2025届高一11班	0.929
+13296
+$\dfrac{\sqrt{5}}{3}$
 
-021739
-20230425	2025届高一12班	1.000
+13297
+A
 
-021740
-20230425	2025届高一12班	1.000
+13298
+B
 
-021741
-20230425	2025届高一12班	1.000	1.000	1.000	0.951
+13299
+C
 
-021742
-20230425	2025届高一12班	0.951
+13300
+(1) $a=4$; (2) 证明略
 
-021743
-20230425	2025届高一12班	0.878
+13301
+(1) $[k\pi+\dfrac\pi 3,k\pi+\dfrac{5\pi}6]$, $k\in \mathbf{Z}$; (2) $A=\dfrac\pi 3$, $b=2$, $S=2\sqrt{3}$
 
-021744
-20230425	2025届高一12班	0.915
+13302
+$(-\infty,0)\cup (1,+\infty)$
 
-021745
-20230425	2025届高一12班	0.951	0.890
+13303
+$\dfrac 32$
 
-021746
-20230425	2025届高一12班	0.890
+13304
+$12\pi$
 
-021747
-20230425	2025届高一12班	0.927
+13305
+$-\dfrac 43$
 
-021748
-20230425	2025届高一12班	0.854
+13306
+$\dfrac 3{16}$
 
-021739
-20230425	2025届高一01班	1.000
+13307
+$y=2x-\mathrm{e}$
 
-021740
-20230425	2025届高一01班	1.000
+13308
+$5$
 
-021741
-20230425	2025届高一01班	1.000	1.000	0.951	0.976
+13309
+$4\pi$
 
-021742
-20230425	2025届高一01班	0.988
+13310
+$-3\le a\le -1$
 
-021743
-20230425	2025届高一01班	0.927
+13311
+$9828$
 
-021744
-20230425	2025届高一01班	0.976
+13312
+C
 
-021745
-20230425	2025届高一01班	0.854	0.780
+13313
+B
 
-021746
-20230425	2025届高一01班	0.805
+13314
+C
 
-021747
-20230425	2025届高一01班	0.927
+13315
+(1) 证明略; (2) $\dfrac{\sqrt{10}}5$
 
-021748
-20230425	2025届高一01班	0.732
+13316
+(1) $a_n=n-1$; (2) 证明略
 
-021739
-20230425	2025届高一04班	0.949
+13317
+$\sqrt{5}$
 
-021740
-20230425	2025届高一04班	0.949
+13318
+$\overrightarrow{AD}=\dfrac 23 \overrightarrow{a}+\dfrac 13 \overrightarrow{b}$
 
-021741
-20230425	2025届高一04班	1.000	1.000	1.000	1.000
+13319
+$\dfrac{16}{35}$
 
-021742
-20230425	2025届高一04班	0.962
+13320
+$[0,8)$
 
-021743
-20230425	2025届高一04班	0.910
+13321
+$\dfrac{25}{9}$
 
-021744
-20230425	2025届高一04班	0.923
+13322
+$[\dfrac 34,1]$
 
-021745
-20230425	2025届高一04班	1.000	0.885
+13323
+$3$
 
-021746
-20230425	2025届高一04班	0.744
+13324
+$0$
 
-021747
-20230425	2025届高一04班	0.897
+13325
+$\dfrac{\sqrt{3}}2$
 
-021748
-20230425	2025届高一04班	0.692
+13326
+$\dfrac 34$
 
-021739
-20230425	2025届高一05班	1.000
+13327
+C
 
-021740
-20230425	2025届高一05班	1.000
+13328
+B
 
-021741
-20230425	2025届高一05班	1.000	1.000	1.000	1.000
+13329
+B
 
-021742
-20230425	2025届高一05班	0.974
+13330
+(1) 证明略; (2) $B_1D=\dfrac 12$
 
-021743
-20230425	2025届高一05班	0.859
+13331
+(1) $\dfrac{x^2}{4}+\dfrac{y^2}{3}=1$, $y\ne 0$; (2) $[12,8\sqrt{3})$;
 
-021744
-20230425	2025届高一05班	1.000
+13332
+$\sqrt{3}$
 
-021745
-20230425	2025届高一05班	0.974	0.885
+13333
+$8$
 
-021746
-20230425	2025届高一05班	0.679
+13334
+$-\dfrac 12$
 
-021747
-20230425	2025届高一05班	0.846
+13335
+$0.14$
 
-021748
-20230425	2025届高一05班	0.667
+13336
+$1$
 
-021739
-20230425	2025届高一06班	1.000
+13337
+$-2$
 
-021740
-20230425	2025届高一06班	0.927
+13338
+$99.9\%$
 
-021741
-20230425	2025届高一06班	0.976	0.976	1.000	0.902
+13339
+$\dfrac 1{15}$
 
-021742
-20230425	2025届高一06班	0.866
+13340
+$4$
 
-021743
-20230425	2025届高一06班	0.951
+13341
+$2$
 
-021744
-20230425	2025届高一06班	1.000
+13342
+A
 
-021745
-20230425	2025届高一06班	0.939	0.793
+13343
+B
 
-021746
-20230425	2025届高一06班	0.646
+13344
+B
 
-021747
-20230425	2025届高一06班	1.000
+13345
+(1) $\dfrac\pi 3$; (2) $\arcsin \dfrac{\sqrt{3}}3$
 
-021748
-20230425	2025届高一06班	0.732
+13346
+(1) $x=15$; (2) 比值为$\dfrac 12$
 
-021739
-20230425	2025届高一08班	1.000
+13347
+$-\dfrac 1{25}$
 
-021740
-20230425	2025届高一08班	0.971
+13348
+$-\dfrac{\sqrt{2}}2$
 
-021741
-20230425	2025届高一08班	1.000	1.000	1.000	1.000
+13349
+$6$
 
-021742
-20230425	2025届高一08班	0.986
+13350
+$(-1,-2)$
 
-021743
-20230425	2025届高一08班	0.986
+13351
+$4$
 
-021744
-20230425	2025届高一08班	0.886
+13352
+$0$
 
-021745
-20230425	2025届高一08班	1.000	0.857
+13353
+$12$
 
-021746
-20230425	2025届高一08班	0.700
+13354
+$1$
 
-021747
-20230425	2025届高一08班	0.971
+13355
+$\dfrac{\sqrt{3}}3$
 
-021748
-20230425	2025届高一08班	0.800
+13356
+$(0,\dfrac 14)$
 
-021739
-20230425	2025届高一09班	0.950
+13357
+B
 
-021740
-20230425	2025届高一09班	0.975
+13358
+A
 
-021741
-20230425	2025届高一09班	0.975	0.975	0.950	1.000
+13359
+D
 
-021742
-20230425	2025届高一09班	0.988
+13360
+(1) $P(0,0)$或$P(-\dfrac 85,\dfrac 45)$; (2) 过定点$(-\dfrac 45,\dfrac 25)$
 
-021743
-20230425	2025届高一09班	0.887
+13361
+(1) $p=\dfrac 23$, $q=\dfrac 14$; (2) $\dfrac 16$
 
-021744
-20230425	2025届高一09班	0.963
+13362
+$\{5,7,9\}$
 
-021745
-20230425	2025届高一09班	0.975	0.863
+13363
+$a+b>2$
 
-021746
-20230425	2025届高一09班	0.762
+13364
+$(0,+\infty)$
 
-021747
-20230425	2025届高一09班	0.975
+13365
+$\dfrac 23$
+
+13366
+$25$
+
+13367
+$(-\infty,-8]\cup [2,+\infty)$
+
+13368
+$\dfrac 52$
+
+13369
+$\dfrac 23$
+
+13370
+\textcircled{2}\textcircled{3}
+
+13371
+$9$
+
+13372
+B
+
+13373
+D
+
+13374
+D
+
+13375
+(1) $x=1$; (2) $[\dfrac 12,+\infty)$
+
+13376
+(1) $\dfrac{x^2}{4}+\dfrac{y^2}{2}=1$; (2) $y=\pm \dfrac{\sqrt{2}}2+1$
+
+
+13377
+$1$
+
+13378
+$\dfrac{5\pi}6$
+
+13379
+$\pi$
+
+13380
+$\dfrac{\sqrt{5}-1}2$
+
+13381
+$1:2\sqrt{2}$
+
+13382
+$\dfrac{x^2}{18}-\dfrac{y^2}{9}=1$
+
+13383
+$0.88$
+
+13384
+$0.95$
+
+13385
+$7$
+
+13386
+$(-\infty,8)$
+
+13387
+D
+
+13388
+A
+
+13389
+C
+
+13390
+(1) $y=\begin{cases}\dfrac{24x-2x^2}{15-x}, & x\in \{1,2,\cdots,9\},\\ \dfrac 53 x-\dfrac{x^3}{180},& x\in \{10,11,\cdots,20\};\end{cases}$ (2) 日进货量为$10$吨时, 日利润最大, 最大日利润是$\dfrac{100}{9}$千元
+
+13391
+(1) $y=2\sin(2x+\dfrac\pi 3)-1$; (2) $[-1,1]$
+
+13392
+$\{-1,2\}$
+
+13393
+$8$
+
+13394
+$7$
+
+13395
+$0.3$
+
+13396
+$0.2$
+
+13397
+$1$
+
+13398
+$6$
+
+13399
+$\mathrm{e}-1$
+
+13400
+$\dfrac{7}{25}$
+
+13401
+\textcircled{1}\textcircled{2}\textcircled{3}\textcircled{5}
+
+13402
+C
+
+13403
+A
+
+13404
+D
+
+13405
+(1) $\dfrac{x^2}{4}+\dfrac{y^2}{2}=1$; (2) $[0,2]$
+
+13406
+(I) (1) 证明略; (2) $S_n=4-\dfrac{n+2}{2^{n-1}}$; (II) 证明略
+
+13407
+$(0,1)\cup (1,2]$
+
+13408
+$-\sqrt{13}$
+
+13409
+$\sqrt{2}$
+
+13410
+$0.0044$
+
+13411
+$20$
+
+13412
+$2$
+
+13413
+$2\sqrt{2}$
+
+13414
+$x=-1$
+
+13415
+$\dfrac\pi 2$
+
+13416
+$-1$
+
+13417
+D
+
+13418
+D
+
+13419
+C
+
+13420
+(1) 证明略; (2) $\dfrac{\sqrt{3}}3$
+
+13421
+(1) $BD=BA$; (2) 约$0.33\text{km}$
+
+13422
+$\dfrac 32$
+
+13423
+$(3,4)$
+
+13424
+$\sqrt{7}$
+
+13425
+$\dfrac{9}{4}$或$\dfrac{4}{9}$
+
+13426
+$\dfrac{24}{25}$
+
+13427
+$\dfrac 34$
+
+13428
+$100$
+
+13429
+$-\dfrac{11}{16}$
+
+13430
+$30$
+
+13431
+$[\dfrac 73,\dfrac{13}{3})$
+
+13432
+B
+
+13433
+B
+
+13434
+A
+
+13435
+(1) $\dfrac{2\sqrt{6}}3$; (2) $\dfrac{\sqrt{10}}2\text{千米}$
+
+13436
+(1) 证明略; (2) $\dfrac{4\sqrt{3}}7$
+
+
+13437
+$\{1,3,5\}$
+
+13438
+$1$
+
+13439
+$2m-1$
+
+13440
+$8$
+
+13441
+$45$
+
+13442
+$\sqrt{5}$
+
+13443
+$\pi-\arctan\dfrac 32$
+
+13444
+$\dfrac{11}{12}$
+
+13445
+$-3$
+
+13446
+$[-2,6]$
+
+13447
+C
+
+13448
+C
+
+13449
+D
+
+13450
+(1) $4\pi$; (2) $\arctan\dfrac{\sqrt{2}}2$
+
+13451
+(1) 第一个数列具有性质$P$, 第二个数列不具有性质$P$; (2) $(-\infty,-2]\cup [0,+\infty)$
+
+
+
+13452
+$\dfrac 34\pi$
+
+13453
+$\sqrt{7}$
+
+13454
+$4$
+
+13455
+$\dfrac{24}{25}$
+
+13456
+$y=\dfrac {1}{\mathrm{e}}x$
+
+13457
+$\dfrac{16}{35}$
+
+13458
+$[1,3]$
+
+13459
+$36$
+
+13460
+$30$
+
+13461
+$\dfrac{2\sqrt{3}}3$
+
+13462
+B
+
+13463
+B
+
+13464
+C
+
+13465
+(1) 证明略; (2) $\dfrac{\sqrt{5}}5$
+
+13466
+(1) $[\dfrac 14,1)$; (2) 当$\theta=\dfrac{\pi}{6}$时
+
+13467
+$-2$
+
+13468
+$2\sqrt{2}$
+
+13469
+$16$
+
+13470
+$\dfrac 14$
+
+13471
+$5$
+
+13472
+$\dfrac{3\pi}{4}$
+
+13473
+$\sqrt{10}$
+
+13474
+$\dfrac{21}{16}$
+
+13475
+\textcircled{1}\textcircled{2}\textcircled{3}\textcircled{4}
+
+13476
+$7$
+
+13477
+B
+
+13478
+A
+
+13479
+C
+
+13480
+(1) $\dfrac 34$; (2) $\dfrac{13}{36}$
+
+13481
+(1) $-1$; (2) $(0,+\infty)$
+
+13482
+$1$
+
+13483
+$60$
+
+13484
+$\dfrac{80}{243}$
+
+13485
+$\dfrac 13$
+
+13486
+$\arccos\dfrac{\sqrt{15}}{10}$
+
+13487
+$2-\dfrac 1n$
+
+13488
+$21$
+
+13489
+$y=\begin{cases}x^2+\dfrac 1x, & x>0, \\ 0, & x=0, \\ -x^2+\dfrac 1x, & x<0\end{cases}$
+
+13490
+$a=2$或$a\ge 2\sqrt{2}$其中的一个即可
+
+13491
+$4$
+
+13492
+A
+
+13493
+C
+
+13494
+B
+
+13495
+(1) $y=x-1$; (2) $(-\infty,\dfrac 32)$
+
+13496
+(1) 证明略; (2) $6\sqrt{2}$
+
+13497
+$6$
+
+13498
+$2$
+
+13499
+$1-k$
+
+13500
+$4$
+
+13501
+$15$
+
+13502
+$(\dfrac 12,1)$
+
+13503
+$0.568$
+
+13504
+$1$
+
+13505
+$\lambda\ge -3$
+
+13506
+$\dfrac{56}3$
+
+13507
+A
+
+13508
+C
+
+13509
+D
+
+13510
+(1) $(3,5)$; (2) $[2,\dfrac 52]$
+
+13511
+(1) 约$16173$升; (2) 从第$13$个月起
 
-021748
-20230425	2025届高一09班	0.725
 

工具/讲义生成.py

@@ -10,22 +10,7 @@ paper_type = 3 # 随后设置一下后续的讲义标题
 """---设置题块编号---"""
 
 problems = [
-# "012295:012297,012301,012305"
-# "012316:012318,012322,012326"
-# "012516:012518,012522,012526"
-# "012537:012539,012543,012547"
-# "012558:012560,012564,012568"
-# "012579:012581,012585,012589"
-# "012600:012602,012606,012610"
-# "012621:012623,012627,012631"
-# "012642:012644,012648,012652"
-# "012663:012665,012669,012673"
-# "012684:012686,012690,012694"
-# "012705:012707,012711,012715"
-# "012726:012728,012732,012736"
-# "012768:012770,012774,012778"
-"014519:014521,014525,014529"
-
+"13527:13541"
 ]
 
 """---设置结束---"""
@@ -44,7 +29,7 @@ elif paper_type == 2:
 elif paper_type == 3:
     enumi_mode = 0 #设置模式(1为整卷统一编号, 0为每一部分从1开始编号)
     template_file = "模板文件/日常选题讲义模板.txt" #设置模板文件名
-    exec_list = [("标题文字待处理","中档题冲刺15")]  #设置讲义标题
+    exec_list = [("标题文字待处理","双基训练11")]  #设置讲义标题
     destination_file = "临时文件/"+exec_list[0][1] # 设置输出文件名