From 87e45b8e7748875e0d601f9b6546d007f9d2add7 Mon Sep 17 00:00:00 2001
From: "weiye.wang" <kj_wangweiye@126.com>
Date: Sat, 18 Nov 2023 23:39:02 +0800
Subject: [PATCH] =?UTF-8?q?=E4=BF=AE=E6=94=B9=E5=9F=BA=E7=A1=80=E7=9F=A5?=
 =?UTF-8?q?=E8=AF=86=E6=95=B0=E6=8D=AE=E5=BA=93=E4=B8=AD=E7=9A=84=E4=B8=80?=
 =?UTF-8?q?=E5=A4=84=E7=AC=94=E8=AF=AF?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 题库0.3/BasicKnowledge.json | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/题库0.3/BasicKnowledge.json b/题库0.3/BasicKnowledge.json
index 52a56cff..824f7c21 100644
--- a/题库0.3/BasicKnowledge.json
+++ b/题库0.3/BasicKnowledge.json
@@ -295,7 +295,7 @@
         "objs": [
             "K0219003B"
         ],
-        "content": "如果$y=f(x)$, 是区间$I$上的严格增函数, 那么$y=2^{f(x)}$是区间$I$上的\\blank{30}函数.\\\\\n    这是因为对区间$I$上任意两个实数$x_1,x_2$, 当$x_1<x_2$时, 因$y=f(x)$是严格增函数, 故\\blank{20}$<$\\blank{20}, 因此\\blank{30}$<$\\blank{30}, 所以$y=2^{f(x)}$在区间$I$上是\\blank{30}函数."
+        "content": "如果$y=f(x)$是区间$I$上的严格增函数, 那么$y=2^{f(x)}$是区间$I$上的\\blank{30}函数.\\\\\n    这是因为对区间$I$上任意两个实数$x_1,x_2$, 当$x_1<x_2$时, 因$y=f(x)$是严格增函数, 故\\blank{20}$<$\\blank{20}, 因此\\blank{30}$<$\\blank{30}, 所以$y=2^{f(x)}$在区间$I$上是\\blank{30}函数."
     },
     "B00042": {
         "lesson": "K0219",