20221209 afternoon
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fc5e41ba64
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 3,
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"execution_count": 1,
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"metadata": {},
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"outputs": [
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{
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"0"
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]
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},
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"execution_count": 3,
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"execution_count": 1,
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"metadata": {},
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"output_type": "execute_result"
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}
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"source": [
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"import os,re,json\n",
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"\"\"\"这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭, 随后运行第二个代码块\"\"\"\n",
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"problems = \"4486\"\n",
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"problems = \"12135\"\n",
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"\n",
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"def generate_number_set(string,dict):\n",
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" string = re.sub(r\"[\\n\\s]\",\"\",string)\n",
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 1,
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3.8.8 ('base')",
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"display_name": "Python 3.9.15 ('pythontest')",
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"language": "python",
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"name": "python3"
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},
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.8"
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"version": "3.9.15"
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},
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"orig_nbformat": 4,
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"vscode": {
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"interpreter": {
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"hash": "d311ffef239beb3b8f3764271728f3972d7b090c974f8e972fcdeedf230299ac"
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"hash": "91219a98e0e9be72efb992f647fe78b593124968b75db0b865552d6787c8db93"
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}
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}
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},
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@ -300141,7 +300141,7 @@
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},
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"012135": {
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"id": "012135",
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"content": "某校运会上无人机飞行表演, 在水平距离$x\\in [10,24]$(单位: 米)内的飞行轨迹如图所示, $y$表示飞行高度(单位: 米).其中当$x\\in [10,20]$时, 轨迹为开口向上的抛物线的一段(端点为$MQ$), 当$x\\in [20,24]$时, 轨迹为线段$QN$, 经测量, 起点$M(10,24)$, 终点$N(24,24)$, 最低点$P(14,8)$.\n\\begin{center}\n\\begin{tikzpicture}[>=latex,scale = 0.1]\n\\draw [->] (-5,0) -- (30,0) node [below] {$x$};\n\\draw [->] (0,-5) -- (0,50) node [left] {$y$};\n\\draw (0,0) node [below left] {$O$};\n\\draw [domain = 10:20] plot (\\x,{pow(\\x-14,2)+8});\n\\draw (20,44) node [above] {$O$} coordinate (O) -- (24,24) node [right] {$N$} (10,24) node [above] {$M$} (14,8) node [below] {$P$} (0,24) node [left] {$A$} coordinate (A);\n\\draw [dashed] (0,24) --++ ({atan(2*sqrt(180)-28)}:25) coordinate (T);\n\\draw [dashed] (0,24) --++ (24,24);\n\\draw (A) pic [\"$\\theta$\", draw, angle eccentricity = 1.5, angle radius = 10] {angle = T--A--O}; \n\\end{tikzpicture}\n\\end{center}\n(1) 求$y$关于$x$的函数解析式;\\\\\n(2) 在$A(0,24)$处有摄像机跟踪拍摄, 为确保始终拍到无人机, 求拍摄视角$\\theta$的最小值.(精确到$0.1^\\circ$)",
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"content": "某校运会上无人机飞行表演, 在水平距离$x\\in [10,24]$(单位: 米)内的飞行轨迹如图所示, $y$表示飞行高度(单位: 米).其中当$x\\in [10,20]$时, 轨迹为开口向上的抛物线的一段(端点为$MQ$), 当$x\\in [20,24]$时, 轨迹为线段$QN$, 经测量, 起点$M(10,24)$, 终点$N(24,24)$, 最低点$P(14,8)$.\n\\begin{center}\n\\begin{tikzpicture}[>=latex,scale = 0.1]\n\\draw [->] (-5,0) -- (30,0) node [below] {$x$};\n\\draw [->] (0,-5) -- (0,50) node [left] {$y$};\n\\draw (0,0) node [below left] {$O$};\n\\draw [domain = 10:20] plot (\\x,{pow(\\x-14,2)+8});\n\\draw (20,44) node [above] {$Q$} coordinate (O) -- (24,24) node [right] {$N$} (10,24) node [above] {$M$} (14,8) node [below] {$P$} (0,24) node [left] {$A$} coordinate (A);\n\\draw [dashed] (0,24) --++ ({atan(2*sqrt(180)-28)}:25) coordinate (T);\n\\draw [dashed] (0,24) --++ (24,24);\n\\draw (A) pic [\"$\\theta$\", draw, angle eccentricity = 1.5, angle radius = 10] {angle = T--A--O}; \n\\end{tikzpicture}\n\\end{center}\n(1) 求$y$关于$x$的函数解析式;\\\\\n(2) 在$A(0,24)$处有摄像机跟踪拍摄, 为确保始终拍到无人机, 求拍摄视角$\\theta$的最小值.(精确到$0.1^\\circ$)",
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"objs": [],
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"tags": [],
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"genre": "解答题",
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