From 9cab605d5a76476d7705d70fe27eb751ff733f04 Mon Sep 17 00:00:00 2001
From: wangweiye7840 <kj_wangweiye@126.com>
Date: Sun, 4 Feb 2024 15:54:50 +0800
Subject: [PATCH] =?UTF-8?q?=E4=BF=AE=E6=94=B921528=E7=AD=94=E6=A1=88?=
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---
 题库0.3/Problems.json | 5 +++--
 1 file changed, 3 insertions(+), 2 deletions(-)

diff --git a/题库0.3/Problems.json b/题库0.3/Problems.json
index 3536d6d9..dacb2658 100644
--- a/题库0.3/Problems.json
+++ b/题库0.3/Problems.json
@@ -584076,7 +584076,7 @@
             "第三单元"
         ],
         "genre": "解答题",
-        "ans": "(1) 当$\\alpha$在第一象限时, $\\sin (2 \\pi-\\alpha)=-\\dfrac{\\sqrt{3}}{2}$;\n当$\\alpha$在第三象限时, $\\sin (2 \\pi-\\alpha)=\\dfrac{\\sqrt{3}}{2}$.\\\\\n(2) 当$\\alpha$在第一象限时, $\\dfrac{1}{\\tan [\\dfrac{(2 k+1) \\pi}{2}+\\alpha]}=-\\sqrt{3}$;\n当$\\alpha$在第四象限时, $\\dfrac{1}{\\tan [\\dfrac{(2 k+1) \\pi}{2}+\\alpha]}=\\sqrt{3}$.",
+        "ans": "(1) 当$\\alpha$在第一象限时, $\\sin (2 \\pi-\\alpha)=-\\dfrac{\\sqrt{3}}{2}$;\n当$\\alpha$在第四象限时, $\\sin (2 \\pi-\\alpha)=\\dfrac{\\sqrt{3}}{2}$.\\\\\n(2) 当$\\alpha$在第一象限时, $\\dfrac{1}{\\tan [\\dfrac{(2 k+1) \\pi}{2}+\\alpha]}=-\\sqrt{3}$;\n当$\\alpha$在第四象限时, $\\dfrac{1}{\\tan [\\dfrac{(2 k+1) \\pi}{2}+\\alpha]}=\\sqrt{3}$.",
         "solution": "",
         "duration": -1,
         "usages": [
@@ -584091,7 +584091,8 @@
         ],
         "origin": "2025届高一下校本作业",
         "edit": [
-            "20230209\t王伟叶"
+            "20230209\t王伟叶",
+            "20240204\t王伟叶"
         ],
         "same": [],
         "related": [],