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修改一些题面与答案

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wangweiye7840 2024-02-21 17:10:16 +08:00
parent b48d3ef568
commit 9e37244a69
1 changed files with 11 additions and 8 deletions
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19
题库0.3/Problems.json
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@ -582422,13 +582422,13 @@
},
"021458": {
"id": "021458",
"content": "完成下列角度与弧度的换算:\n\\begin{center}\n\\begin{tabular}{|c|c|c|c|c|c|c|c|}\n\\hline 角度数 &$15^{\\circ}$&$105^{\\circ}$&$225^{\\circ}$&\\blank{15} &\\blank{15} &\\blank{15} &\\blank{15} \\\\\n\\hline 弧度数 &\\blank{15} &\\blank{15} &\\blank{15} &$\\dfrac{5 \\pi}{3}$&$\\dfrac{9 \\pi}{5}$&$\\dfrac{7 \\pi}{4}$&$\\dfrac{3}{2}$\\\\\n\\hline\n\\end{tabular}\n\\end{center}",
"content": "完成下列角度与弧度的换算:\n\\begin{center}\n\\begin{tabular}{|c|c|c|c|c|c|c|c|}\n\\hline 角度数 &$15^{\\circ}$&$105^{\\circ}$&$225^{\\circ}$& \\underline{\\hbox to 3pt{} (1) \\hbox to 3pt{}} & \\underline{\\hbox to 3pt{} (2) \\hbox to 3pt{}} & \\underline{\\hbox to 3pt{} (3) \\hbox to 3pt{}} & \\underline{\\hbox to 3pt{} (4) \\hbox to 3pt{}} \\\\\n\\hline 弧度数 & \\underline{\\hbox to 3pt{} (5) \\hbox to 3pt{}} & \\underline{\\hbox to 3pt{} (6) \\hbox to 3pt{}} & \\underline{\\hbox to 3pt{} (7) \\hbox to 3pt{}} &$\\dfrac{5 \\pi}{3}$&$\\dfrac{9 \\pi}{5}$&$\\dfrac{7 \\pi}{4}$&$\\dfrac{3}{2}$\\\\\n\\hline\n\\end{tabular}\n\\end{center}",
"objs": [],
"tags": [
"第三单元"
],
"genre": "填空题",
"ans": "$\\dfrac{\\pi}{12}$; $\\dfrac{7\\pi}{12}$; $\\dfrac{5\\pi}{4}$; $300^{\\circ}$; $324^{\\circ}$; $315^{\\circ}$; $(\\dfrac{270}{\\pi})^{\\circ}$",
"ans": "$300^{\\circ}$; $324^{\\circ}$; $315^{\\circ}$; $(\\dfrac{270}{\\pi})^{\\circ}$; $\\dfrac{\\pi}{12}$; $\\dfrac{7\\pi}{12}$; $\\dfrac{5\\pi}{4}$",
"solution": "",
"duration": -1,
"usages": [
@ -582441,7 +582441,8 @@
],
"origin": "2025届高一下校本作业",
"edit": [
"20230209\t王伟叶"
"20230209\t王伟叶",
"20240221\t王伟叶"
],
"same": [],
"related": [],
@ -582515,7 +582516,7 @@
"第三单元"
],
"genre": "填空题",
"ans": "(1)$\\frac{\\pi}{3}$;(2)$\\frac{2\\pi}{3}$",
"ans": "$\\dfrac{\\pi}{3}$; $\\dfrac{2\\pi}{3}$",
"solution": "",
"duration": -1,
"usages": [
@ -582528,7 +582529,8 @@
],
"origin": "2025届高一下校本作业",
"edit": [
"20230209\t王伟叶"
"20230209\t王伟叶",
"20240221\t王伟叶"
],
"same": [],
"related": [],
@ -582659,13 +582661,13 @@
},
"021466": {
"id": "021466",
"content": "用弧度制写出下图中的阴影部分表示的角的集合(包括边界).\\\\\n(1) \\blank{100};\n\\begin{center}\n\\begin{tikzpicture}[>=latex]\n\\fill [gray!25] (0,0) --++ (-45:1.5) arc (-45:90:1.5);\n\\draw [->] (-2,0) -- (2,0) node [below] {$x$} coordinate (x);\n\\draw [->] (0,-2) -- (0,2) node [left] {$y$} coordinate (y);\n\\draw (0,0) node [below left] {$O$} coordinate (O);\n\\draw (0,0) --++ (-45:1.5) coordinate (T);\n\\draw pic [draw, \"$45^\\circ$\", scale = 0.5, angle eccentricity = 2.5] {angle = T--O--x};\n\\end{tikzpicture}\n\\end{center}\n(2) \\blank{100}.\n\\begin{center}\n\\begin{tikzpicture}[>=latex]\n\\fill [gray!25] (0,0) --++ (30:1.5) arc (30:150:1.5);\n\\fill [gray!25] (0,0) --++ (-30:1.5) arc (-30:-150:1.5);\n\\draw [->] (-2,0) -- (2,0) node [below] {$x$} coordinate (x);\n\\draw [->] (0,-2) -- (0,2) node [left] {$y$} coordinate (y);\n\\draw (0,0) node [below left] {$O$} coordinate (O);\n\\draw (0,0) --++ (30:1.5) coordinate (T);\n\\draw (0,0) --++ (-30:1.5) (0,0) --++ (-150:1.5);\n\\draw (0,0) --++ (150:1.5) coordinate (S);\n\\draw pic [draw, \"$30^\\circ$\", scale = 0.5, angle eccentricity = 3] {angle = x--O--T};\n\\draw (-2,0) coordinate (x1);\n\\draw pic [draw, \"$30^\\circ$\", scale = 0.5, angle eccentricity = 3] {angle = S--O--x1};\n\\end{tikzpicture}\n\\end{center}",
"content": "用弧度制写出下图中的阴影部分表示的角的集合(包括边界).\\\\\n(1) \\blank{100};\n\\begin{center}\n\\begin{tikzpicture}[>=latex]\n\\fill [pattern = north east lines] (0,0) --++ (-45:1.5) arc (-45:90:1.5);\n\\draw [->] (-2,0) -- (2,0) node [below] {$x$} coordinate (x);\n\\draw [->] (0,-2) coordinate (y')-- (0,2) node [left] {$y$} coordinate (y);\n\\draw (0,0) node [below left] {$O$} coordinate (O);\n\\draw (0,0) --++ (-45:1.5) coordinate (T);\n\\draw pic [draw, \"$45^\\circ$\", scale = 0.5, angle eccentricity = 2.5] {angle = y'--O--T};\n\\end{tikzpicture}\n\\end{center}\n(2) \\blank{100}.\n\\begin{center}\n\\begin{tikzpicture}[>=latex]\n\\fill [pattern = north east lines] (0,0) --++ (30:1.5) arc (30:150:1.5);\n\\fill [pattern = north east lines] (0,0) --++ (-30:1.5) arc (-30:-150:1.5);\n\\draw [->] (-2,0) -- (2,0) node [below] {$x$} coordinate (x);\n\\draw [->] (0,-2) -- (0,2) node [left] {$y$} coordinate (y);\n\\draw (0,0) node [below left] {$O$} coordinate (O);\n\\draw (0,0) --++ (30:1.5) coordinate (T);\n\\draw (0,0) --++ (-30:1.5) (0,0) --++ (-150:1.5);\n\\draw (0,0) --++ (150:1.5) coordinate (S);\n\\draw pic [draw, \"$30^\\circ$\", scale = 0.5, angle eccentricity = 3] {angle = x--O--T};\n\\draw (-2,0) coordinate (x1);\n\\draw pic [draw, \"$30^\\circ$\", scale = 0.5, angle eccentricity = 3] {angle = S--O--x1};\n\\end{tikzpicture}\n\\end{center}",
"objs": [],
"tags": [
"第三单元"
],
"genre": "填空题",
"ans": "(1) $\\{\\alpha|-\\frac{\\pi}{4}+2k\\pi \\le \\alpha \\le \\frac{\\pi}{2}+2k\\pi,\\ k \\in \\mathbf{Z}\\}$;\\\\\n(2) $\\{\\alpha|\\frac{\\pi}{6}+k\\pi \\le \\alpha \\le \\frac{5\\pi}{6}+k\\pi,\\ k \\in \\mathbf{Z}\\}$.",
"ans": "(1) $\\{\\alpha|-\\frac{\\pi}{4}+2k\\pi \\le \\alpha \\le \\frac{\\pi}{2}+2k\\pi,\\ k \\in \\mathbf{Z}\\}$; (2) $\\{\\alpha|\\frac{\\pi}{6}+k\\pi \\le \\alpha \\le \\frac{5\\pi}{6}+k\\pi,\\ k \\in \\mathbf{Z}\\}$.",
"solution": "",
"duration": -1,
"usages": [
@ -582679,7 +582681,8 @@
"origin": "2025届高一下校本作业",
"edit": [
"20230209\t王伟叶",
"20240131\t王伟叶"
"20240131\t王伟叶",
"20240221\t王伟叶"
],
"same": [],
"related": [],