diff --git a/题库0.3/Problems.json b/题库0.3/Problems.json
index 987eea87..372c45ab 100644
--- a/题库0.3/Problems.json
+++ b/题库0.3/Problems.json
@@ -652697,7 +652697,7 @@
     },
     "024023": {
         "id": "024023",
-        "content": "设 $a$、$b \\in R$, 若集合 $\\{1, a+b, a\\}=\\{0, b, \\dfrac{b}{a}\\}$, 则 $a^{2023}+b^{2023}=$\\blank{50}.",
+        "content": "设 $a$、$b \\in \\mathbf{R}$, 若集合 $\\{1, a+b, a\\}=\\{0, b, \\dfrac{b}{a}\\}$, 则 $a^{2023}+b^{2023}=$\\blank{50}.",
         "objs": [],
         "tags": [
             "第一单元"
@@ -652709,7 +652709,8 @@
         "usages": [],
         "origin": "自拟题目",
         "edit": [
-            "20240125\t毛培菁"
+            "20240125\t毛培菁",
+            "20240130\t王伟叶"
         ],
         "same": [],
         "related": [],
@@ -654426,7 +654427,7 @@
     },
     "024099": {
         "id": "024099",
-        "content": "已知数列 $\\{a_n\\}$ 的首项 $a_1>0$, $a_{n+1}=\\dfrac{3 a_n}{2 a_n+1}$($n \\in N$, $n \\geq 1$), 且 $a_1=\\dfrac{2}{3}$.\\\\\n(1) 求证: $\\{\\dfrac{1}{a_n}-1\\}$ 是等比数列, 并求出 $\\{a_n\\}$ 的通项公式;\\\\\n(2) 求数列 $\\{\\dfrac{1}{a_n}\\}$ 的前 $n$ 项和 $T_n$.",
+        "content": "已知数列 $\\{a_n\\}$ 的首项 $a_1>0$, $a_{n+1}=\\dfrac{3 a_n}{2 a_n+1}$($n \\in \\mathbf{N}$, $n \\geq 1$), 且 $a_1=\\dfrac{2}{3}$.\\\\\n(1) 求证: $\\{\\dfrac{1}{a_n}-1\\}$ 是等比数列, 并求出 $\\{a_n\\}$ 的通项公式;\\\\\n(2) 求数列 $\\{\\dfrac{1}{a_n}\\}$ 的前 $n$ 项和 $T_n$.",
         "objs": [],
         "tags": [
             "第四单元"
@@ -654438,7 +654439,8 @@
         "usages": [],
         "origin": "自拟题目",
         "edit": [
-            "20240125\t毛培菁"
+            "20240125\t毛培菁",
+            "20240130\t王伟叶"
         ],
         "same": [],
         "related": [],