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20220915 evening

This commit is contained in:
Wang Weiye 2022-09-15 16:57:16 +08:00
parent 98e3803b2b
commit a7fd2ac432
5 changed files with 102 additions and 46 deletions
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21
工具/批量添加题库字段数据.ipynb
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@ -2,28 +2,17 @@
"cells": [ "cells": [
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 1, "execution_count": 5,
"metadata": {}, "metadata": {},
"outputs": [ "outputs": [
{ {
"name": "stdout", "name": "stdout",
"output_type": "stream", "output_type": "stream",
"text": [ "text": [
"题号: 001339 , 字段: remark 中已添加数据: 可能是因为没有复习过, 学生做得比想象得差.\n", "题号: 004184 , 字段: objs 中已添加数据: K0203002B\n",
"题号: 002859 , 字段: remark 中已添加数据: 学生很少会从定义域出发去考虑奇偶性问题，考虑定义域的学生中还有一部分是说``因为定义域关于原点对称，所以$b=1$''.\n", "题号: 004184 , 字段: objs 中已添加数据: K0205002B\n",
"题号: 011131 , 字段: remark 中已添加数据: 最值能够取到学生还是有一些不写（周双表示都扣了4分）.\n", "题号: 004184 , 字段: objs 中已添加数据: K0215005B\n",
"题号: 002968 , 字段: remark 中已添加数据: 第(2)小题学生极少能关注到定义域.\n", "题号: 004184 , 字段: objs 中已添加数据: K0221002B\n"
"题号: 003884 , 字段: remark 中已添加数据: 有点抽象, 反例难举.\n",
"题号: 001221 , 字段: remark 中已添加数据: 第(3)小题有学生未考虑定义域，有学生在化简过程中出现了分母为$x$.\n",
"题号: 009517 , 字段: remark 中已添加数据: 学生举不来反例, 有的只考虑了$f(0)$,$f(1)$,$f(2)$的值. 还有一些长篇大论不举反例的.\n",
"题号: 001331 , 字段: remark 中已添加数据: 太难了，不适合作为第一轮讲义的题目. 太难了，不适合作为第一轮讲义的题目. 太难了，不适合作为第一轮讲义的题目.\n",
"题号: 009522 , 字段: remark 中已添加数据: 第(2)小题学生很多不会分三种情况讨论. 第(1)小题有些学生把自变量取在$(-3,0]$.\n",
"题号: 002884 , 字段: remark 中已添加数据: 少数学生不能分辨``定义域上单调''和``分若干个区间单调''.\n",
"题号: 004265 , 字段: remark 中已添加数据: 第(2)小题有点难, 用分离变量和二次函数讨论做对的都有, 但是对面上太难了.\n",
"题号: 010197 , 字段: remark 中已添加数据: 可能需要加一个``用函数观点求解''\n",
"题号: 003013 , 字段: remark 中已添加数据: 许多学生的答案是开区间, 可能是用了零点存在定理.\n",
"题号: 000555 , 字段: remark 中已添加数据: 题目非常难, 通过同样题目的测验确定讲解是否有效.\n",
"题号: 001227 , 字段: remark 中已添加数据: 学生有些未想到求导, 瞎猜的答案.\n"
] ]
} }
], ],

6
工具/添加关联题目.ipynb
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@ -2,15 +2,15 @@
"cells": [ "cells": [
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": null, "execution_count": 2,
"metadata": {}, "metadata": {},
"outputs": [], "outputs": [],
"source": [ "source": [
"import os,re,json,time\n", "import os,re,json,time\n",
"\n", "\n",
"\"\"\"---设置原题目id与新题目id---\"\"\"\n", "\"\"\"---设置原题目id与新题目id---\"\"\"\n",
"old_id = \"734\"\n", "old_id = \"6033\"\n",
"new_id = \"30018\"\n", "new_id = \"30020\"\n",
"\"\"\"---设置完毕---\"\"\"\n", "\"\"\"---设置完毕---\"\"\"\n",
"\n", "\n",
"old_id = old_id.zfill(6)\n", "old_id = old_id.zfill(6)\n",

27
工具/讲义生成.ipynb
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@ -2,7 +2,7 @@
"cells": [ "cells": [
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 1, "execution_count": 5,
"metadata": {}, "metadata": {},
"outputs": [ "outputs": [
{ {
@ -13,9 +13,11 @@
"题块 1 处理完毕.\n", "题块 1 处理完毕.\n",
"正在处理题块 2 .\n", "正在处理题块 2 .\n",
"题块 2 处理完毕.\n", "题块 2 处理完毕.\n",
"开始编译教师版本pdf文件: 临时文件/和差倍角公式_教师_20220914.tex\n", "正在处理题块 3 .\n",
"题块 3 处理完毕.\n",
"开始编译教师版本pdf文件: 临时文件/周末卷03初稿_教师_20220915.tex\n",
"0\n", "0\n",
"开始编译学生版本pdf文件: 临时文件/和差倍角公式_学生_20220914.tex\n", "开始编译学生版本pdf文件: 临时文件/周末卷03初稿_学生_20220915.tex\n",
"0\n" "0\n"
] ]
} }
@ -28,29 +30,30 @@
"\"\"\"---设置模式结束---\"\"\"\n", "\"\"\"---设置模式结束---\"\"\"\n",
"\n", "\n",
"\"\"\"---设置模板文件名---\"\"\"\n", "\"\"\"---设置模板文件名---\"\"\"\n",
"template_file = \"模板文件/第一轮复习讲义模板.tex\"\n", "# template_file = \"模板文件/第一轮复习讲义模板.tex\"\n",
"# template_file = \"模板文件/测验周末卷模板.tex\"\n", "template_file = \"模板文件/测验周末卷模板.tex\"\n",
"\"\"\"---设置模板文件名结束---\"\"\"\n", "\"\"\"---设置模板文件名结束---\"\"\"\n",
"\n", "\n",
"\"\"\"---设置其他预处理替换命令---\"\"\"\n", "\"\"\"---设置其他预处理替换命令---\"\"\"\n",
"#2023届第一轮讲义更换标题\n", "#2023届第一轮讲义更换标题\n",
"exec_list = [(\"标题数字待处理\",\"12\"),(\"标题文字待处理\",\"和差倍角公式\")] \n", "# exec_list = [(\"标题数字待处理\",\"12\"),(\"标题文字待处理\",\"和差倍角公式\")] \n",
"enumi_mode = 0\n", "# enumi_mode = 0\n",
"\n", "\n",
"#2023届测验卷与周末卷\n", "#2023届测验卷与周末卷\n",
"# exec_list = [(\"标题替换\",\"测验卷02\")]\n", "exec_list = [(\"标题替换\",\"周末卷03\")]\n",
"# enumi_mode = 1\n", "enumi_mode = 1\n",
"\"\"\"---其他预处理替换命令结束---\"\"\"\n", "\"\"\"---其他预处理替换命令结束---\"\"\"\n",
"\n", "\n",
"\"\"\"---设置目标文件名---\"\"\"\n", "\"\"\"---设置目标文件名---\"\"\"\n",
"destination_file = \"临时文件/和差倍角公式\"\n", "destination_file = \"临时文件/周末卷03初稿\"\n",
"\"\"\"---设置目标文件名结束---\"\"\"\n", "\"\"\"---设置目标文件名结束---\"\"\"\n",
"\n", "\n",
"\n", "\n",
"\"\"\"---设置题号数据---\"\"\"\n", "\"\"\"---设置题号数据---\"\"\"\n",
"problems = [\n", "problems = [\n",
"\"3092,3094,6115,3095,3097,3102,3113,3114,3100,6147,4548,3125,8168,5086,3093,6286\",\n", "\"10965:10976\",\n",
"\"6138,3105,6163,6166,6190,6129,6177,6126,6214,8170,3107,6288\"\n", "\"10977:10980\",\n",
"\"10981:10985\"\n",
"]\n", "]\n",
"\"\"\"---设置题号数据结束---\"\"\"\n", "\"\"\"---设置题号数据结束---\"\"\"\n",
"\n", "\n",

10
工具/题号选题pdf生成.ipynb
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@ -2,16 +2,16 @@
"cells": [ "cells": [
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 5, "execution_count": 3,
"metadata": {}, "metadata": {},
"outputs": [ "outputs": [
{ {
"name": "stdout", "name": "stdout",
"output_type": "stream", "output_type": "stream",
"text": [ "text": [
"开始编译教师版本pdf文件: 临时文件/月考备选_教师用_20220914.tex\n", "开始编译教师版本pdf文件: 临时文件/周末卷3初稿_教师用_20220915.tex\n",
"0\n", "0\n",
"开始编译学生版本pdf文件: 临时文件/月考备选_学生用_20220914.tex\n", "开始编译学生版本pdf文件: 临时文件/周末卷3初稿_学生用_20220915.tex\n",
"0\n" "0\n"
] ]
} }
@ -26,14 +26,14 @@
"\"\"\"---设置题目列表---\"\"\"\n", "\"\"\"---设置题目列表---\"\"\"\n",
"#留空为编译全题库\n", "#留空为编译全题库\n",
"problems = r\"\"\"\n", "problems = r\"\"\"\n",
"4080,4059,4122,4143,4125,4312,4248,4249,4354,4392,4449,4335,4451,4431,4228,4557,4432,4642,4276,4316,4149,4417,8170,4089,4356,4416,4320,4339,4415,4217,4359,109,4153,4175,4382,6033,4091,4500,4366,4384,4400,8101,4401,4522,4094,4157,4305,4440,4370,4139,4224,4328,4350,4407,4444,4184,4247,\n", "10965:10985\n",
"\n", "\n",
"\"\"\"\n", "\"\"\"\n",
"\"\"\"---设置题目列表结束---\"\"\"\n", "\"\"\"---设置题目列表结束---\"\"\"\n",
"\n", "\n",
"\"\"\"---设置文件名---\"\"\"\n", "\"\"\"---设置文件名---\"\"\"\n",
"#目录和文件的分隔务必用/\n", "#目录和文件的分隔务必用/\n",
"filename = \"临时文件/月考备选\"\n", "filename = \"临时文件/周末卷3初稿\"\n",
"\"\"\"---设置文件名结束---\"\"\"\n", "\"\"\"---设置文件名结束---\"\"\"\n",
"\n", "\n",
"\n", "\n",

84
题库0.3/Problems.json
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@ -99069,7 +99069,6 @@
"id": "004122", "id": "004122",
"content": "若$\\sin\\alpha=\\dfrac 14$, 则$\\sin(\\pi+\\alpha)=$\\blank{50}.", "content": "若$\\sin\\alpha=\\dfrac 14$, 则$\\sin(\\pi+\\alpha)=$\\blank{50}.",
"objs": [ "objs": [
"K0304003B",
"K0306002B" "K0306002B"
], ],
"tags": [ "tags": [
@ -99496,9 +99495,8 @@
"id": "004139", "id": "004139",
"content": "已知常数$a\\in \\mathbf{R}^+$, 函数$f(x)=3^x+a^2\\cdot 3^{-x}$.\\\\\n(1) 若$a=\\sqrt{3}$, 解关于$x$的不等式$f(x)<4$;\\\\\n(2) 若$f(x)$在$[3,+\\infty)$上为增函数, 求$a$的取值范围.", "content": "已知常数$a\\in \\mathbf{R}^+$, 函数$f(x)=3^x+a^2\\cdot 3^{-x}$.\\\\\n(1) 若$a=\\sqrt{3}$, 解关于$x$的不等式$f(x)<4$;\\\\\n(2) 若$f(x)$在$[3,+\\infty)$上为增函数, 求$a$的取值范围.",
"objs": [ "objs": [
"K0219002B", "K0211001B",
"K0220001B", "K0219003B"
"K0223005B"
], ],
"tags": [ "tags": [
"第二单元" "第二单元"
@ -100609,7 +100607,12 @@
"004184": { "004184": {
"id": "004184", "id": "004184",
"content": "设$m$为给定的实常数, 若函数$y=f(x)$在其定义域内存在实数$x_0$, 使得$f(x_0+m)=f(x_0)+f(m)$成立, 则称函数$f(x)$为``$G(m)$函数''.\\\\\n(1) 若函数$f(x)=2^x$为``$G(2)$函数'', 求实数$x_0$的值;\\\\\n(2) 若函数$f(x)=\\lg \\dfrac a{x^2+1}$为``$G(1)$函数'', 求实数$a$的取值范围;\\\\\n(3) 已知$f(x)=x+b$($b\\in \\mathbf{R}$)为``$G(0)$函数'', 设$g(x)=x|x-4|$. 若对任意的$x_1,x_2\\in[0,t]$, 当$x_1\\ne x_2$时, 都有$\\dfrac{g(x_1)-g(x_2)}{f(x_1)-f(x_2)}>2$成立, 求实数$t$的最大值.", "content": "设$m$为给定的实常数, 若函数$y=f(x)$在其定义域内存在实数$x_0$, 使得$f(x_0+m)=f(x_0)+f(m)$成立, 则称函数$f(x)$为``$G(m)$函数''.\\\\\n(1) 若函数$f(x)=2^x$为``$G(2)$函数'', 求实数$x_0$的值;\\\\\n(2) 若函数$f(x)=\\lg \\dfrac a{x^2+1}$为``$G(1)$函数'', 求实数$a$的取值范围;\\\\\n(3) 已知$f(x)=x+b$($b\\in \\mathbf{R}$)为``$G(0)$函数'', 设$g(x)=x|x-4|$. 若对任意的$x_1,x_2\\in[0,t]$, 当$x_1\\ne x_2$时, 都有$\\dfrac{g(x_1)-g(x_2)}{f(x_1)-f(x_2)}>2$成立, 求实数$t$的最大值.",
"objs": [], "objs": [
"K0203002B",
"K0205002B",
"K0215005B",
"K0221002B"
],
"tags": [ "tags": [
"第二单元" "第二单元"
], ],
@ -102791,7 +102794,9 @@
"004276": { "004276": {
"id": "004276", "id": "004276",
"content": "若函数$f(x)=\\log_2(2^x+1)+kx$是偶函数, 则$k=$\\blank{50}.", "content": "若函数$f(x)=\\log_2(2^x+1)+kx$是偶函数, 则$k=$\\blank{50}.",
"objs": [], "objs": [
"K0218001B"
],
"tags": [ "tags": [
"第二单元" "第二单元"
], ],
@ -103866,7 +103871,10 @@
"004320": { "004320": {
"id": "004320", "id": "004320",
"content": "设$a\\in \\mathbf{R}$. 若函数$y=f(x)$是奇函数, 且$x>0$时, $f(x)=a(x-1)+1$. 若$y=f(x)$是单调增函数, 则$a$取值范围为\\blank{50}.", "content": "设$a\\in \\mathbf{R}$. 若函数$y=f(x)$是奇函数, 且$x>0$时, $f(x)=a(x-1)+1$. 若$y=f(x)$是单调增函数, 则$a$取值范围为\\blank{50}.",
"objs": [], "objs": [
"K0219001B",
"K0220003B"
],
"tags": [ "tags": [
"第二单元" "第二单元"
], ],
@ -104052,7 +104060,9 @@
"004328": { "004328": {
"id": "004328", "id": "004328",
"content": "经济订货批量模型, 是目前大多数工厂、企业等最常采用的订货方式, 即某种物资在单位时间的需求量为某常数, 经过某段时间后, 存储量消耗下降到零, 此时开始订货并随即到货, 然后开始下一个存储周期. 该模型适用于整批间隔进货、不允许缺货的存储问题. 具体如下:\\\\\n年存储成本费$T$(元)关于每次订货$x$(单位: 吨)的函数关系为$T(x)=\\dfrac{Bx}2+\\dfrac{AC}x$, 其中$A$为年需求量, $B$为每单位物资的年存储费, $C$为每次订货费.\\\\\n某化工厂需用甲醇作为原料, 年需求量为$6000$吨, 每吨存储费为$120$元/年, 每次订货费为$2500$元.\n(1) 若该化工厂每次订购$300$吨甲醇, 求年存储成本费;\\\\\n(2) 每次需订购多少吨甲醇, 可使该化工厂年存储成本费最少? 最少费用为多少?", "content": "经济订货批量模型, 是目前大多数工厂、企业等最常采用的订货方式, 即某种物资在单位时间的需求量为某常数, 经过某段时间后, 存储量消耗下降到零, 此时开始订货并随即到货, 然后开始下一个存储周期. 该模型适用于整批间隔进货、不允许缺货的存储问题. 具体如下:\\\\\n年存储成本费$T$(元)关于每次订货$x$(单位: 吨)的函数关系为$T(x)=\\dfrac{Bx}2+\\dfrac{AC}x$, 其中$A$为年需求量, $B$为每单位物资的年存储费, $C$为每次订货费.\\\\\n某化工厂需用甲醇作为原料, 年需求量为$6000$吨, 每吨存储费为$120$元/年, 每次订货费为$2500$元.\n(1) 若该化工厂每次订购$300$吨甲醇, 求年存储成本费;\\\\\n(2) 每次需订购多少吨甲醇, 可使该化工厂年存储成本费最少? 最少费用为多少?",
"objs": [], "objs": [
"K0222002B"
],
"tags": [ "tags": [
"第二单元" "第二单元"
], ],
@ -144366,7 +144376,9 @@
"20220720\t王伟叶" "20220720\t王伟叶"
], ],
"same": [], "same": [],
"related": [], "related": [
"030020"
],
"remark": "", "remark": "",
"space": "12ex" "space": "12ex"
}, },
@ -191000,7 +191012,9 @@
"20220726\t王伟叶" "20220726\t王伟叶"
], ],
"same": [], "same": [],
"related": [], "related": [
"030019"
],
"remark": "", "remark": "",
"space": "12ex" "space": "12ex"
}, },
@ -279829,5 +279843,55 @@
], ],
"remark": "", "remark": "",
"space": "" "space": ""
},
"030019": {
"id": "030019",
"content": "把$5\\sin \\alpha -12\\cos \\alpha$化成$A\\sin (\\alpha +\\varphi)$($A>0$)的形式, 所得结果为\\blank{50}.",
"objs": [
"K0311002B"
],
"tags": [
"第三单元"
],
"genre": "填空题",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "二期课改练习册高一第二学期-20220915修改",
"edit": [
"20220726\t王伟叶"
],
"same": [],
"related": [
"008170"
],
"remark": "",
"space": ""
},
"030020": {
"id": "030020",
"content": "设$x$是第二象限角, 且满足$\\cos \\dfrac x2+\\sin \\dfrac x2=-\\dfrac{\\sqrt 5}2$, 则$\\sin \\dfrac x2-\\cos \\dfrac x2=$\\blank{50}.",
"objs": [
"K0305001B"
],
"tags": [
"第三单元"
],
"genre": "填空题",
"ans": "",
"solution": "",
"duration": -1,
"usages": [],
"origin": "代数精编第四章三角函数-20220915修改",
"edit": [
"20220720\t王伟叶"
],
"same": [],
"related": [
"006033"
],
"remark": "",
"space": ""
} }
} }