diff --git a/备课组/26届/lessons.json b/备课组/26届/lessons.json
index ffc9ebb4..75396cf2 100644
--- a/备课组/26届/lessons.json
+++ b/备课组/26届/lessons.json
@@ -635,21 +635,17 @@
             "019296"
         ],
         "work_inclass": [
-            "009462",
-            "010079",
-            "010086"
+            "009462"
         ],
         "homework": [
+            "010079",
             "019295",
             "020169",
             "020170",
             "020171",
             "020172",
             "020173",
-            "020174",
-            "020175",
-            "020176",
-            "019297",
+            "019838",
             "019298"
         ],
         "remarks": ""
@@ -669,6 +665,7 @@
         ],
         "examples_basic": [
             "011841",
+            "009464",
             "011842",
             "011844",
             "011845",
@@ -681,21 +678,17 @@
         ],
         "work_inclass": [
             "009463",
-            "009464",
-            "010089",
-            "010097",
-            "010099"
+            "010089"
         ],
         "homework": [
             "020186",
             "020189",
-            "020190",
-            "020191",
             "020193",
             "020194",
+            "010099",
             "020195",
             "020196",
-            "020197",
+            "010097",
             "020198"
         ],
         "remarks": ""
diff --git a/题库0.3/Problems.json b/题库0.3/Problems.json
index f2378a43..ffba605e 100644
--- a/题库0.3/Problems.json
+++ b/题库0.3/Problems.json
@@ -518407,7 +518407,7 @@
     },
     "020193": {
         "id": "020193",
-        "content": "若$a>0$, $b>0$, 且$a\\ne b$, 则下列各式恒成立的是\\bracket{20}.\n\\fourch{$\\dfrac{2ab}{a+b}<\\dfrac{a+b}2<\\sqrt {ab}$}{$\\sqrt {ab}<\\dfrac{2ab}{a+b}<\\dfrac{a+b}2$}{$\\dfrac{2ab}{a+b}<\\sqrt {ab}<\\dfrac{a+b}2$}{$\\sqrt {ab}<\\dfrac{a+b}2<\\dfrac{2ab}{a+b}$}",
+        "content": "若$a>0$, $b>0$, 且$a\\ne b$, 则下列各式恒成立的是\\bracket{20}.\n\\twoch{$\\dfrac{2ab}{a+b}<\\dfrac{a+b}2<\\sqrt {ab}$}{$\\sqrt {ab}<\\dfrac{2ab}{a+b}<\\dfrac{a+b}2$}{$\\dfrac{2ab}{a+b}<\\sqrt {ab}<\\dfrac{a+b}2$}{$\\sqrt {ab}<\\dfrac{a+b}2<\\dfrac{2ab}{a+b}$}",
         "objs": [],
         "tags": [
             "第一单元"
@@ -518419,7 +518419,8 @@
         "usages": [],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20230925\t王伟叶"
         ],
         "same": [
             "005017"
@@ -518453,7 +518454,7 @@
     },
     "020195": {
         "id": "020195",
-        "content": "设$ab\\ne 0$, 利用基本不等式有如下证明:\\\\ \n$\\dfrac ba+\\dfrac ab=\\dfrac{b^2+a^2}{ab}\\ge \\dfrac{2ab}{ab}=2$.试判断这个证明过程是否正确. 若正确, 请说明每一步的依据; 若不正确, 请说明理由.",
+        "content": "设$ab\\ne 0$, 利用基本不等式有如下证明: $\\dfrac ba+\\dfrac ab=\\dfrac{b^2+a^2}{ab}\\ge \\dfrac{2ab}{ab}=2$.试判断这个证明过程是否正确. 若正确, 请说明每一步的依据; 若不正确, 请说明理由.",
         "objs": [],
         "tags": [
             "第一单元"
@@ -518465,7 +518466,8 @@
         "usages": [],
         "origin": "2025届高一校本作业必修第二章",
         "edit": [
-            "20220901\t王伟叶\t伍杨超"
+            "20220901\t王伟叶\t伍杨超",
+            "20230925\t王伟叶"
         ],
         "same": [
             "007818"