修改14785题面
This commit is contained in:
parent
3860bf8584
commit
cb7992a403
|
|
@ -1,6 +1,6 @@
|
|||
import os,re,json
|
||||
"""这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭"""
|
||||
problems = "14697"
|
||||
problems = "14758"
|
||||
editor = "王伟叶"
|
||||
|
||||
def generate_number_set(string,dict):
|
||||
|
|
|
|||
|
|
@ -388980,7 +388980,7 @@
|
|||
},
|
||||
"014758": {
|
||||
"id": "014758",
|
||||
"content": "数学家们在探寻自然对数底$\\mathrm{e} \\approx 2.71828$与圆周率$\\pi$之间的联系时, 发现了以下公式($\\mathrm{i}$为虚数单位):\\\\\n(I) $\\mathrm{e}^x=1+\\dfrac{x}{1 !}+\\dfrac{x^2}{2 !}+\\dfrac{x^3}{3 !}+\\cdots+\\dfrac{x^n}{n !}+\\cdots$;\\\\\n(II) $\\sin x=\\dfrac{x}{1 !}-\\dfrac{x^3}{3 !}+\\dfrac{x^5}{5 !}-\\dfrac{x^7}{7 !}+\\cdots+(-1)^{n-1} \\dfrac{x^{2 n-1}}{(2 n-1) !}+\\cdots$;\\\\\n(III) $\\cos x=1-\\dfrac{x^2}{2 !}+\\dfrac{x^4}{4 !}-\\dfrac{x^6}{6 !}+\\cdots+(-1)^{n-1} \\dfrac{x^{2 n-2}}{(2 n-2) !}+\\cdots$.\\\\\n上述公式中, $x \\in \\mathbf{C}$, $n \\in \\mathbf{N}$, $n\\ge 1$, 据此判断, 当$x\\in \\mathbf{C}$时, 以下命题\n\\textcircled{1} $\\mathrm{e}^{\\mathrm{i}x}=\\cos x+\\mathrm{i} \\sin x$; \n\\textcircled{2} $\\mathrm{e}^{\\mathrm{i}x}=\\sin x+\\mathrm{i} \\cos x$; \n\\textcircled{3} $\\mathrm{e}^{\\mathrm{i} \\pi}+1=0$; \n\\textcircled{4} $\\mathrm{e}^{\\mathrm{i} \\pi}+i=0$; \n\\textcircled{5} $|\\mathrm{e}^{\\mathrm{i}x}+\\mathrm{e}^{-\\mathrm{i}x}| \\leq 2$中, 正确的个数是\\bracket{20}.\n\\fourch{$1$个}{$2$个}{$3$个}{$4$个}",
|
||||
"content": "数学家们在探寻自然对数底$\\mathrm{e} \\approx 2.71828$与圆周率$\\pi$之间的联系时, 发现了以下公式($\\mathrm{i}$为虚数单位):\\\\\n(I) $\\mathrm{e}^x=1+\\dfrac{x}{1 !}+\\dfrac{x^2}{2 !}+\\dfrac{x^3}{3 !}+\\cdots+\\dfrac{x^n}{n !}+\\cdots$;\\\\\n(II) $\\sin x=\\dfrac{x}{1 !}-\\dfrac{x^3}{3 !}+\\dfrac{x^5}{5 !}-\\dfrac{x^7}{7 !}+\\cdots+(-1)^{n-1} \\dfrac{x^{2 n-1}}{(2 n-1) !}+\\cdots$;\\\\\n(III) $\\cos x=1-\\dfrac{x^2}{2 !}+\\dfrac{x^4}{4 !}-\\dfrac{x^6}{6 !}+\\cdots+(-1)^{n-1} \\dfrac{x^{2 n-2}}{(2 n-2) !}+\\cdots$.\\\\\n上述公式中, $x \\in \\mathbf{C}$, $n \\in \\mathbf{N}$, $n\\ge 1$, 据此判断, 当$x\\in \\mathbf{C}$时, 以下命题\n\\textcircled{1} $\\mathrm{e}^{\\mathrm{i}x}=\\cos x+\\mathrm{i} \\sin x$; \n\\textcircled{2} $\\mathrm{e}^{\\mathrm{i}x}=\\sin x+\\mathrm{i} \\cos x$; \n\\textcircled{3} $\\mathrm{e}^{\\mathrm{i} \\pi}+1=0$; \n\\textcircled{4} $\\mathrm{e}^{\\mathrm{i} \\pi}+\\mathrm{i}=0$; \n\\textcircled{5} $|\\mathrm{e}^{\\mathrm{i}x}+\\mathrm{e}^{-\\mathrm{i}x}| \\leq 2$中, 正确的个数是\\bracket{20}.\n\\fourch{$1$个}{$2$个}{$3$个}{$4$个}",
|
||||
"objs": [],
|
||||
"tags": [],
|
||||
"genre": "选择题",
|
||||
|
|
@ -389003,7 +389003,8 @@
|
|||
],
|
||||
"origin": "23届宝山区混合式教学适应性练习试题16",
|
||||
"edit": [
|
||||
"20230314\t王伟叶"
|
||||
"20230314\t王伟叶",
|
||||
"20230621\t王伟叶"
|
||||
],
|
||||
"same": [],
|
||||
"related": [],
|
||||
|
|
|
|||
Reference in New Issue