修改15300至15302题面
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@ -1,6 +1,6 @@
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import os,re,json
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"""这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭"""
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problems = "13347"
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problems = "15300:15302"
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editor = "王伟叶"
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def generate_number_set(string,dict):
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@ -397920,7 +397920,7 @@
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},
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"015300": {
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"id": "015300",
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"content": "已知函数$f(x)=x+\\dfrac{a}{x}+b$, $x \\in[b,+\\infty)$, 其中$b>0$, $a \\in \\mathbf{R}$, 若$f(x)$的最小值为$2$, 则实数$a$的取值范周是\\blank{50}.",
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"content": "已知函数$f(x)=x+\\dfrac{a}{x}+b$, $x \\in[b,+\\infty)$, $a \\in \\mathbf{R}$, 若存在$b\\in (0,+\\infty)$, 使得$f(x)$的最小值为$2$, 则实数$a$的取值范围是\\blank{50}.",
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"objs": [],
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"tags": [
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"第二单元"
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@ -397932,7 +397932,8 @@
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"usages": [],
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"origin": "2023届徐汇区高三二模试题11",
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"edit": [
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"20230419\t王伟叶"
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"20230419\t王伟叶",
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"20230509\t王伟叶"
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],
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"same": [],
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"related": [],
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@ -397942,7 +397943,7 @@
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},
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"015301": {
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"id": "015301",
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"content": "已知数列$\\{a_n\\}$溚足: 对于任意$n \\in \\mathbf{N}$, $n\\ge 1$, 有$a_n \\in(0, \\dfrac{\\pi}{2})$, 且$a_1=\\dfrac{\\pi}{4}$, $f(a_{n+1})=\\sqrt{f'(a_n)}$, 其中$f(x)=\\tan x$. 若$b_n=\\dfrac{(-1)^n}{\\tan a_{n+1}-\\tan a_n}$, 数列$\\{b_n\\}$的前$n$项和为$T_n$, 则$T_{120}=$\\blank{50}.",
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"content": "已知数列$\\{a_n\\}$满足: 对于任意$n \\in \\mathbf{N}$, $n\\ge 1$, 有$a_n \\in(0, \\dfrac{\\pi}{2})$, 且$a_1=\\dfrac{\\pi}{4}$, $f(a_{n+1})=\\sqrt{f'(a_n)}$, 其中$f(x)=\\tan x$. 若$b_n=\\dfrac{(-1)^n}{\\tan a_{n+1}-\\tan a_n}$, 数列$\\{b_n\\}$的前$n$项和为$T_n$, 则$T_{120}=$\\blank{50}.",
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"objs": [],
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"tags": [
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"第二单元",
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@ -397956,7 +397957,8 @@
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"usages": [],
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"origin": "2023届徐汇区高三二模试题12",
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"edit": [
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"20230419\t王伟叶"
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"20230419\t王伟叶",
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"20230509\t王伟叶"
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],
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"same": [],
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"related": [],
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@ -397966,7 +397968,7 @@
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},
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"015302": {
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"id": "015302",
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"content": "已知$z \\in \\mathbf{C}$, 则``$z+\\overline {z}=0$''是``$\\mathrm{z}$为纯虚数''的\\bracket{20}.\n\\twoch{充分非必要条件}{必要非充分条件}{充要条件}{既非充分又非必要条件}",
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"content": "已知$z \\in \\mathbf{C}$, 则``$z+\\overline {z}=0$''是``$z$为纯虚数''的\\bracket{20}.\n\\twoch{充分非必要条件}{必要非充分条件}{充要条件}{既非充分又非必要条件}",
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"objs": [],
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"tags": [
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"第五单元"
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@ -397978,7 +397980,8 @@
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"usages": [],
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"origin": "2023届徐汇区高三二模试题13",
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"edit": [
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"20230419\t王伟叶"
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"20230419\t王伟叶",
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"20230509\t王伟叶"
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],
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"same": [],
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"related": [],
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