ans 15122 $\{0,1,2\}$ 15123 $1$ 15124 $\sqrt{5}$ 15125 $\dfrac{x^2}{\frac{11}3}+\dfrac{y^2}{\frac{11}2}=1$($\dfrac{3x^2}{11}+\dfrac{2y^2}{11}=1$) 15126 $-\dfrac 23$ 15127 $3$ 15128 $(0,\dfrac 12]$ 15129 $(\dfrac 14,\dfrac{\sqrt{3}}4)$ 15130 $y=0.186x+11.571$ 15131 $\dfrac{\sqrt{2}}2$ 15132 $95.4$(或者$95.5$也可以) 15133 $1+2\lg 2$ 15134 C 15135 B 15136 A 15137 D 15138 (1) 证明略; (2) $2^{n+2}-4-3n$ 15139 (1) $\dfrac 23$; (2) 证明略 15140 (1) $2\sqrt{3}$; (2) $\sqrt{2}$ 15141 (1) 分布为$\begin{pmatrix}0 & 1 & 2 \\ \dfrac 15 & \dfrac 35 & \dfrac 15\end{pmatrix}$, 期望为$1$; (2) $\chi^2\approx 0.595$, 脑瘤病患在左右侧的部位与习惯在哪一侧接听手机电话无关 15142 (1) $2x-y-2\ln 2=0$; (2) $-a-\dfrac 12$; (3) 有且仅有一个零点 15143 $(-1,1)$ 15144 $\pi$ 15145 $2$ 15146 $9$ 15147 $(-\infty,0)\cup [\dfrac 13,+\infty)$ 15148 $-\dfrac 17$ 15149 $36\pi$ 15150 $14$ 15151 $68$ 15152 $3$ 15153 $(-\dfrac 12,0)$ 15154 $3\sqrt{5}$ 15155 A 15156 D 15157 B 15158 D 15159 (1) 证明略; (2) $8\sqrt{3}$ 15160 (1) $[1,+\infty)$; (2) $10216$ 15161 (1) $\dfrac 13$; (2) $1.2$ 15162 (1) $2$; (2) $(-1,\dfrac 74)$; (3) 是定值$\sqrt{6}$ 15163 (1) $(1,+\infty)$; (2) $[-1,\dfrac 32]$; (3) 证明略 15164 $\{-1,1\}$ 15165 $10$ 15166 $\dfrac 12$ 15167 $18\pi$ 15168 $2$ 15169 $0.2$ 15170 $12$ 15171 $\dfrac 14$ 15172 $[-2,+\infty)$ 15173 $\sqrt{2}$ 15174 $[\dfrac 76,\dfrac{15}2]$ 15175 $\dfrac{-3\pm \sqrt{6}}6$ 15176 D 15177 C 15178 B 15179 C 15180 (1) $\dfrac 13$; (2) $8\sqrt{2}$ 15181 (1) 证明略; (2) $\dfrac{4\sqrt{21}}{21}$ 15182 (1) $0.01998$; (2) 分布为$\begin{pmatrix}0 & 1 & 2 & 3 \\ 0.00000 & 0.00030 & 0.02940 & 0.97030 \end{pmatrix}$, 期望为$2.97$ 15183 (1) 离心率为$\dfrac{\sqrt{5}}2$, 渐近线方程为$y=\pm \dfrac 12 x$; (2) $1$; (3) 证明略 15184 (1) $-4$; (2) 存在切线$l_2$与$l_1$垂直, 理由略; (3) $(\dfrac{3-\sqrt{5}}{2},\dfrac 12]\cup [2,\dfrac{3+\sqrt{5}}{2})$ 15185 $\{2,4\}$ 15186 $(-\infty,1)$ 15187 $0.2$ 15188 $(1,+\infty)$ 15189 $\dfrac{2\sqrt{2}}3\pi$ 15190 $1$ 15191 $0.8$ 15192 $4$ 15193 $3$ 15194 $[-1,1]$ 15195 $3$ 15196 $\dfrac{\sqrt{21}}{14}$ 15197 D 15198 A 15199 C 15200 B 15201 (1) 证明略; (2) 分布为$\begin{pmatrix} 0 & 1 & 2 \\ \dfrac 3{10} & \dfrac 35 & \dfrac{1}{10}\end{pmatrix}$, 期望为$\dfrac 45$ 15202 (1) 证明略; (2) $60^\circ$ 15203 (1) $\lambda \approx 29.21$, 估计到$2023$年底该地新能源汽车保有量约$40.3$万辆; (2) $\hat{\lambda}\approx 29.67$, $\hat{r}\approx 0.32$ 15204 (1) $\dfrac{x^2}4+\dfrac{y^2}3=1$; (2) $1$; (3) 值恒为$-3$, 证明略 15205 (1) 振幅为$\sqrt{2}$, 周期为$2\pi$, 初相位为$\dfrac{\pi}{4}$; (2) $(\dfrac{\pi}{3},\dfrac{5\pi}3]$; (3) $(0,1)$ 15206 $\{1\}$ 15207 $5$ 15208 $-1$ 15209 $0.94$ 15210 $-\dfrac{24}{7}$ 15211 $28$ 15212 $50$ 15213 $\dfrac 13$ 15214 $\dfrac 8{11}$ 15215 $9$ 15216 $\dfrac{\sqrt{2}}2$ 15217 $\sqrt{15}a$ 15218 B 15219 B 15220 C 15221 B 15222 (1) $\dfrac \pi 3$; (2) $\dfrac 32$ 15223 (1) 证明略; (2) $\arctan\dfrac{2\sqrt{5}}5$ 15224 (1) $43.3$亿元; (2) (i) 全款购车两年后资产总额为$0.0322a$万元, 分期付款购车两年后资产总额为$0.0233a$万元, 应选择全款购车; (ii) $a<21.2134$, 这一措施对购买A, B, C车型有效 15225 (1) $C_1:\dfrac{x^2}2+y^2=1$, $C_2:\dfrac{x^2}2-y^2=1$; (2) $y=\dfrac 12 x$或$y=-\dfrac 12 x$; (3) $2$ 15226 (1) $g(x)=f(h(x))$; (2) 导函数为$2(2x)^{2x}(1+\ln (2x))$, 最小值为$(\dfrac 1{\mathrm{e}})^{\frac 1{\mathrm{e}}}$; (3) 证明略