20230316 noon
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 3,
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"execution_count": 1,
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"metadata": {},
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"outputs": [
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{
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"0"
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]
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},
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"execution_count": 3,
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"execution_count": 1,
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"metadata": {},
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"output_type": "execute_result"
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}
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"source": [
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"import os,re,json\n",
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"\"\"\"这里编辑题号(列表)后将在vscode中打开窗口, 编辑后保存关闭, 随后运行第二个代码块\"\"\"\n",
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"problems = \"31310\"\n",
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"problems = \"31329\"\n",
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"\n",
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"def generate_number_set(string,dict):\n",
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" string = re.sub(r\"[\\n\\s]\",\"\",string)\n",
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 3,
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"execution_count": 1,
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"metadata": {},
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"outputs": [
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{
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"高三下学期测验01.tex\n",
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"高三下学期测验02.tex\n",
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"高三下学期测验03.tex\n",
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"高三下学期测验04.tex\n",
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"高三下学期测验05.tex\n",
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"高三下学期周末卷01.tex\n",
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"高三下学期周末卷02.tex\n",
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"cells": [
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{
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"cell_type": "code",
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"execution_count": 5,
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"execution_count": 1,
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"metadata": {},
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"outputs": [
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{
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"题块 2 处理完毕.\n",
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"正在处理题块 3 .\n",
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"题块 3 处理完毕.\n",
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"开始编译教师版本pdf文件: 临时文件/高三下学期测验04_教师_20230314.tex\n",
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"开始编译教师版本pdf文件: 临时文件/高三下学期测验04_教师_20230316.tex\n",
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"0\n",
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"开始编译学生版本pdf文件: 临时文件/高三下学期测验04_学生_20230314.tex\n",
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"开始编译学生版本pdf文件: 临时文件/高三下学期测验04_学生_20230316.tex\n",
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"0\n"
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]
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}
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"\"\"\"---设置题块编号---\"\"\"\n",
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"\n",
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"problems = [\n",
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"\"14743:14754\",\"14755:14758\",\"14759:14763\"\n",
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"\"31311:31322\",\"31323:31326\",\"31327:31331\"\n",
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"]\n",
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"\n",
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"\"\"\"---设置结束---\"\"\"\n",
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@ -440767,7 +440767,7 @@
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},
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"031329": {
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"id": "031329",
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"content": "雨天外出虽然有撑雨伞, 时常却总免不了淋湿衣袖、裤脚、背包等, 小明想通过数学建模的方法研究如何撑伞可以让淋湿的面积尽量小. 为了简化问题小明做出下列假设:\\\\\n假设 1: 在网上查阅了人均身高和肩宽的数据后, 小明把人假设为身高、肩宽分别为$170 \\text{cm}$、$40 \\text{cm}$的矩形``纸片人'';\\\\\n假设 2: 受风的影响, 雨滴下落轨迹视为与水平地面所成角为$60^{\\circ}$的直线;\\\\\n假设 3: 伞柄$OT$长为$60 \\text{cm}$, 可绕矩形``纸片人''上点$O$旋转;\\\\\n假设 4: 伞面为被伞柄$OT$垂直平分的线段$AB$, $AB=120 \\text{cm}$.\\\\\n以如图$1$方式撑伞矩形``纸片人''将淋湿``裤脚''; 以如图$2$方式撑伞矩形``纸片人''将淋湿``头和肩膀''(``裤脚''也会有一小部分被淋湿).\n\\begin{center}\n\\begin{tikzpicture}[>=latex,scale = 0.7]\n\\begin{scope}\n\\clip (-3,0) rectangle (3,6);\n\\draw (0,0) -- (0,3.4) -- (0.8,3.4) node [below right] {$O$} coordinate (O) -- (0.8,0);\n\\draw (O) --++ (60:1.2) node [above right] {$T$} coordinate (T);\n\\draw (T) --++ (150:1.2) node [left] {$A$} coordinate (A);\n\\draw (T) --++ (-30:1.2) node [right] {$B$} coordinate (B);\n\\draw (A) ++ (60:1) --++ (60:-15);\n\\draw (B) ++ (60:1) --++ (60:-15);\n\\end{scope}\n\\draw (-3,0) -- (3,0);\n\\end{tikzpicture}\n\\begin{tikzpicture}[>=latex,scale = 0.7]\n\\begin{scope}\n\\clip (-3,0) rectangle (3,6);\n\\draw (0,0) -- (0,3.4) -- (0.8,3.4) node [below right] {$O$} coordinate (O) -- (0.8,0);\n\\draw (O) --++ (20:1.2) node [above right] {$T$} coordinate (T);\n\\draw (T) --++ (110:1.2) node [left] {$A$} coordinate (A);\n\\draw (T) --++ (-70:1.2) node [right] {$B$} coordinate (B);\n\\draw (A) ++ (60:1) --++ (60:-15);\n\\draw (B) ++ (60:1) --++ (60:-15);\n\\end{scope}\n\\draw (-3,0) -- (3,0);\n\\end{tikzpicture}\n\\begin{tikzpicture}[>=latex,scale = 0.7]\n\\begin{scope}\n\\clip (-3,0) rectangle (3.5,6);\n\\draw (0,0) -- (0,3.4) -- (0.8,3.4) node [below right] {$O$} coordinate (O) -- (0.8,0);\n\\draw (O) --++ (39.09484:1.2) node [above right] {$T$} coordinate (T);\n\\draw (T) --++ (129.09484:1.2) node [left] {$A$} coordinate (A);\n\\draw (T) --++ ({39.09484-90}:1.2) node [right] {$B$} coordinate (B);\n\\draw (A) ++ (60:1) --++ (60:-15);\n\\draw (B) ++ (60:1) --++ (60:-15);\n\\end{scope}\n\\draw (-3,0) -- (3,0);\n\\end{tikzpicture}\n\\end{center}\n(1) 如图$3$在矩形``纸片人''上身恰好不被淋湿时, 求其``裤脚''被淋湿 (阴影) 部分的面积(结果精确到$0.1 \\text{cm}^2)$;\\\\\n(2) 请根据你的生活经验对小明建立的数学模型提两条改进建议. (无需求解改进后的模型, 如果建议超过两条仅对前两条评分)",
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"content": "雨天外出虽然有撑雨伞, 时常却总免不了淋湿衣袖、裤脚、背包等, 小明想通过数学建模的方法研究如何撑伞可以让淋湿的面积尽量小. 为了简化问题小明做出下列假设:\\\\\n假设 1: 在网上查阅了人均身高和肩宽的数据后, 小明把人假设为身高、肩宽分别为$170 \\text{cm}$、$40 \\text{cm}$的矩形``纸片人'';\\\\\n假设 2: 受风的影响, 雨滴下落轨迹视为与水平地面所成角为$60^{\\circ}$的直线;\\\\\n假设 3: 伞柄$OT$长为$60 \\text{cm}$, 可绕矩形``纸片人''上点$O$旋转;\\\\\n假设 4: 伞面为被伞柄$OT$垂直平分的线段$AB$, $AB=120 \\text{cm}$.\\\\\n以如图$1$方式撑伞矩形``纸片人''将淋湿``裤脚''; 以如图$2$方式撑伞矩形``纸片人''将淋湿``头和肩膀''(``裤脚''也会有一小部分被淋湿).\n\\begin{center}\n\\begin{tikzpicture}[>=latex,scale = 0.7]\n\\begin{scope}\n\\clip (-3,0) rectangle (3,6);\n\\draw (0,0) -- (0,3.4) -- (0.8,3.4) node [below right] {$O$} coordinate (O) -- (0.8,0);\n\\draw (O) --++ (60:1.2) node [above right] {$T$} coordinate (T);\n\\draw (T) --++ (150:1.2) node [left] {$A$} coordinate (A);\n\\draw (T) --++ (-30:1.2) node [right] {$B$} coordinate (B);\n\\draw (A) ++ (60:1) --++ (60:-15);\n\\draw (B) ++ (60:1) --++ (60:-15);\n\\end{scope}\n\\draw (-3,0) -- (3,0);\n\\draw (0,0) node [below] {图$1$};\n\\end{tikzpicture}\n\\begin{tikzpicture}[>=latex,scale = 0.7]\n\\begin{scope}\n\\clip (-3,0) rectangle (3,6);\n\\draw (0,0) -- (0,3.4) -- (0.8,3.4) node [below right] {$O$} coordinate (O) -- (0.8,0);\n\\draw (O) --++ (20:1.2) node [above right] {$T$} coordinate (T);\n\\draw (T) --++ (110:1.2) node [left] {$A$} coordinate (A);\n\\draw (T) --++ (-70:1.2) node [right] {$B$} coordinate (B);\n\\draw (A) ++ (60:1) --++ (60:-15);\n\\draw (B) ++ (60:1) --++ (60:-15);\n\\end{scope}\n\\draw (-3,0) -- (3,0);\n\\draw (0,0) node [below] {图$2$};\n\\end{tikzpicture}\n\\begin{tikzpicture}[>=latex,scale = 0.7]\n\\begin{scope}\n\\clip (-3,0) rectangle (3.5,6);\n\\filldraw [gray!50] (0.62586,0) -- (0.8,0) -- (0.8,0.3016) -- cycle;\n\\draw (0,0) -- (0,3.4) -- (0.8,3.4) node [below right] {$O$} coordinate (O) -- (0.8,0);\n\\draw (O) --++ (39.09484:1.2) node [above right] {$T$} coordinate (T);\n\\draw (T) --++ (129.09484:1.2) node [left] {$A$} coordinate (A);\n\\draw (T) --++ ({39.09484-90}:1.2) node [right] {$B$} coordinate (B);\n\\draw (A) ++ (60:1) --++ (60:-15);\n\\draw (B) ++ (60:1) --++ (60:-15);\n\\end{scope}\n\\draw (-3,0) -- (3,0);\n\\draw (0,0) node [below] {图$3$};\n\\end{tikzpicture}\n\\end{center}\n(1) 如图$3$在矩形``纸片人''上身恰好不被淋湿时, 求其``裤脚''被淋湿 (阴影) 部分的面积(结果精确到$0.1 \\text{cm}^2)$;\\\\\n(2) 请根据你的生活经验对小明建立的数学模型提两条改进建议. (无需求解改进后的模型, 如果建议超过两条仅对前两条评分)",
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"objs": [],
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"tags": [],
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"genre": "",
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