修改18081题面的错误及19837答案的错误
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@ -474325,21 +474325,22 @@
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},
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"018081": {
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"id": "018081",
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"content": "设$f(x)=\\ln x$, 函数$y=f(x)$的图像为$\\gama$. 作以下操作: 在$\\gama$上取点$A_1(a_1, f(a_1))$, 以$A_1$为切点作$\\gama$的切线交$y$轴于点$(0,a_2)$, 若$a_2>0$, 则在$\\gama$上取点$A_2(a_2,f(a_2))$, 以$A_2$为切点作$\\gama$的切线交$y$轴于点$(0,a_3)$,若$a_3>0$则依此下去……, 一旦$a_n\\leq 0(n\\geq 2)$则终止这一操作. 由此得到数列$\\{a_n\\}$.\\\\\n(1) 对于$\\{a_n\\}$中任意一项$a_m(m \\geq 2)$, 证明: $a_m=\\ln a_{m-1}-1$;\\\\\n(2) 对于$\\{a_n\\}$中任意一项$a_m(m \\geq 2)$, 比较$a_m$与$a_{m-1}-2$大小;\\\\\n(3) 是否存在$a_1$与正整数$k(k\\geq 3)$, 使得$\\{a_n\\}$的前$k$项$a_1, a_2 \\cdots a_k$依次成等差数列? 若存在, 求出$k$的所有可能取值; 若不存在, 说明理由.",
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"content": "设$f(x)=\\ln x$, 函数$y=f(x)$的图像为$\\gamma$. 作以下操作: 在$\\gamma$上取点$A_1(a_1, f(a_1))$, 以$A_1$为切点作$\\gamma$的切线交$y$轴于点$(0,a_2)$, 若$a_2>0$, 则在$\\gamma$上取点$A_2(a_2,f(a_2))$, 以$A_2$为切点作$\\gamma$的切线交$y$轴于点$(0,a_3)$,若$a_3>0$则依此下去……, 一旦$a_n\\leq 0(n\\geq 2)$则终止这一操作. 由此得到数列$\\{a_n\\}$.\\\\\n(1) 对于$\\{a_n\\}$中任意一项$a_m(m \\geq 2)$, 证明: $a_m=\\ln a_{m-1}-1$;\\\\\n(2) 对于$\\{a_n\\}$中任意一项$a_m(m \\geq 2)$, 比较$a_m$与$a_{m-1}-2$大小;\\\\\n(3) 是否存在$a_1$与正整数$k(k\\geq 3)$, 使得$\\{a_n\\}$的前$k$项$a_1, a_2 \\cdots a_k$依次成等差数列? 若存在, 求出$k$的所有可能取值; 若不存在, 说明理由.",
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"objs": [],
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"tags": [
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"第二单元",
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"第四单元"
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],
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"genre": "解答题",
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"ans": "(1)证明略;(2)$a_m\\le a_{m-1}-2$,当且仅当$a_{m-1}=1$时等号成立;(3)${3}$",
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"ans": "(1)证明略;(2)$a_m\\le a_{m-1}-2$,当且仅当$a_{m-1}=1$时等号成立;(3)$\\{3\\}$",
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"solution": "",
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"duration": -1,
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"usages": [],
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"origin": "2023年秋考试题21",
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"edit": [
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"20230608\t王伟叶",
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"20230608\t王伟叶"
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"20230608\t王伟叶",
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"20231001\t王伟叶"
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],
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"same": [],
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"related": [],
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@ -513638,14 +513639,15 @@
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"第一单元"
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],
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"genre": "4em",
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"ans": "$",
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"ans": "",
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"solution": "",
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"duration": -1,
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"usages": [],
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"origin": "2025届高一校本作业必修第二章-20230918修改",
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"edit": [
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"20220901\t王伟叶\t伍杨超",
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"20230918\t王伟叶"
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"20230918\t王伟叶",
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"20231001\t王伟叶"
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],
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"same": [],
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"related": [
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