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mathdeptv2/工具/文本文件/metadata.txt

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ans
15122
$\{0,1,2\}$
15123
$1$
15124
$\sqrt{5}$
15125
$\dfrac{x^2}{\frac{11}3}+\dfrac{y^2}{\frac{11}2}=1$($\dfrac{3x^2}{11}+\dfrac{2y^2}{11}=1$)
15126
$-\dfrac 23$
15127
$3$
15128
$(0,\dfrac 12]$
15129
$(\dfrac 14,\dfrac{\sqrt{3}}4)$
15130
$y=0.186x+11.571$
15131
$\dfrac{\sqrt{2}}2$
15132
$95.4$(或者$95.5$也可以)
15133
$1+2\lg 2$
15134
C
15135
B
15136
A
15137
D
15138
(1) 证明略; (2) $2^{n+2}-4-3n$
15139
(1) $\dfrac 23$; (2) 证明略
15140
(1) $2\sqrt{3}$; (2) $\sqrt{2}$
15141
(1) 分布为$\begin{pmatrix}0 & 1 & 2 \\ \dfrac 15 & \dfrac 35 & \dfrac 15\end{pmatrix}$, 期望为$1$; (2) $\chi^2\approx 0.595$, 脑瘤病患在左右侧的部位与习惯在哪一侧接听手机电话无关
15142
(1) $2x-y-2\ln 2=0$; (2) $-a-\dfrac 12$; (3) 有且仅有一个零点
15143
$(-1,1)$
15144
$\pi$
15145
$2$
15146
$9$
15147
$(-\infty,0)\cup [\dfrac 13,+\infty)$
15148
$-\dfrac 17$
15149
$36\pi$
15150
$14$
15151
$68$
15152
$3$
15153
$(-\dfrac 12,0)$
15154
$3\sqrt{5}$
15155
A
15156
D
15157
B
15158
D
15159
(1) 证明略; (2) $8\sqrt{3}$
15160
(1) $[1,+\infty)$; (2) $10216$
15161
(1) $\dfrac 13$; (2) $1.2$
15162
(1) $2$; (2) $(-1,\dfrac 74)$; (3) 是定值$\sqrt{6}$
15163
(1) $(1,+\infty)$; (2) $[-1,\dfrac 32]$; (3) 证明略
15164
$\{-1,1\}$
15165
$10$
15166
$\dfrac 12$
15167
$18\pi$
15168
$2$
15169
$0.2$
15170
$12$
15171
$\dfrac 14$
15172
$[-2,+\infty)$
15173
$\sqrt{2}$
15174
$[\dfrac 76,\dfrac{15}2]$
15175
$\dfrac{-3\pm \sqrt{6}}6$
15176
D
15177
C
15178
B
15179
C
15180
(1) $\dfrac 13$; (2) $8\sqrt{2}$
15181
(1) 证明略; (2) $\dfrac{4\sqrt{21}}{21}$
15182
(1) $0.01998$; (2) 分布为$\begin{pmatrix}0 & 1 & 2 & 3 \\ 0.00000 & 0.00030 & 0.02940 & 0.97030 \end{pmatrix}$, 期望为$2.97$
15183
(1) 离心率为$\dfrac{\sqrt{5}}2$, 渐近线方程为$y=\pm \dfrac 12 x$; (2) $1$; (3) 证明略
15184
(1) $-4$; (2) 存在切线$l_2$与$l_1$垂直, 理由略; (3) $(\dfrac{3-\sqrt{5}}{2},\dfrac 12]\cup [2,\dfrac{3+\sqrt{5}}{2})$
15185
$\{2,4\}$
15186
$(-\infty,1)$
15187
$0.2$
15188
$(1,+\infty)$
15189
$\dfrac{2\sqrt{2}}3\pi$
15190
$1$
15191
$0.8$
15192
$4$
15193
$3$
15194
$[-1,1]$
15195
$3$
15196
$\dfrac{\sqrt{21}}{14}$
15197
D
15198
A
15199
C
15200
B
15201
(1) 证明略; (2) 分布为$\begin{pmatrix} 0 & 1 & 2 \\ \dfrac 3{10} & \dfrac 35 & \dfrac{1}{10}\end{pmatrix}$, 期望为$\dfrac 45$
15202
(1) 证明略; (2) $60^\circ$
15203
(1) $\lambda \approx 29.21$, 估计到$2023$年底该地新能源汽车保有量约$40.3$万辆; (2) $\hat{\lambda}\approx 29.67$, $\hat{r}\approx 0.32$
15204
(1) $\dfrac{x^2}4+\dfrac{y^2}3=1$; (2) $1$; (3) 值恒为$-3$, 证明略
15205
(1) 振幅为$\sqrt{2}$, 周期为$2\pi$, 初相位为$\dfrac{\pi}{4}$; (2) $(\dfrac{\pi}{3},\dfrac{5\pi}3]$; (3) $(0,1)$
15206
$\{1\}$
15207
$5$
15208
$-1$
15209
$0.94$
15210
$-\dfrac{24}{7}$
15211
$28$
15212
$50$
15213
$\dfrac 13$
15214
$\dfrac 8{11}$
15215
$9$
15216
$\dfrac{\sqrt{2}}2$
15217
$\sqrt{15}a$
15218
B
15219
B
15220
C
15221
B
15222
(1) $\dfrac \pi 3$; (2) $\dfrac 32$
15223
(1) 证明略; (2) $\arctan\dfrac{2\sqrt{5}}5$
15224
(1) $43.3$亿元; (2) (i) 全款购车两年后资产总额为$0.0322a$万元, 分期付款购车两年后资产总额为$0.0233a$万元, 应选择全款购车; (ii) $a<21.2134$, 这一措施对购买A, B, C车型有效
15225
(1) $C_1:\dfrac{x^2}2+y^2=1$, $C_2:\dfrac{x^2}2-y^2=1$; (2) $y=\dfrac 12 x$或$y=-\dfrac 12 x$; (3) $2$
15226
(1) $g(x)=f(h(x))$; (2) 导函数为$2(2x)^{2x}(1+\ln (2x))$, 最小值为$(\dfrac 1{\mathrm{e}})^{\frac 1{\mathrm{e}}}$; (3) 证明略